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Helga [31]
3 years ago
12

Write a function rule that gives the total cost c(p) of p pounds of sugar if each pound costs $0.42.

Mathematics
2 answers:
julia-pushkina [17]3 years ago
5 0
Since a pound of sugar increases proportionally to the total cost of sugar bought, then the function can be written as:

c(p) = 0.42p

Where: c(p) = total cost of sugar bought
p = pounds of sugar

c(p) is a function of p, because c(p) depends on p.
soldi70 [24.7K]3 years ago
3 0

Answer: The function rule that gives the total cost is given by

C(p)=0.42p

Step-by-step explanation:

Let the number of pounds of sugar be 'p'.

Let the total cost would be C(p).

Cost of each pound = $0.42

So, the function rule would be

C(p)=0.42p

Hence, the function rule that gives the total cost is given by

C(p)=0.42p

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Dan invests £1300 into his bank account.
alexandr402 [8]

Given parameters:

Principal  = £1300

Interest rate  = 5%

Duration  = 2yrs

Unknown:

Total amount of Dan's principal = ?

To solve this problem, we apply the equation below:

  Total investment worth  = Principal + interest

   Interest  = \frac{PRT}{100}

where P is the principal

          R is the rate

          T is the time

Now, input the parameters;

     Total investment worth  = £1300 + £ \frac{1300 x 5 x 2}{100}

                                             = £1300 + £130

                                             = £1430

The amount after two years is £1430

7 0
3 years ago
Work out the area of abcd.<br><br> please ensure you give workings out too.
ipn [44]

Answer:

\displaystyle A_{\text{Total}}\approx45.0861\approx45.1

Step-by-step explanation:

We can use the trigonometric formula for the area of a triangle:

\displaystyle A=\frac{1}{2}ab\sin(C)

Where a and b are the side lengths, and C is the angle <em>between</em> the two side lengths.

As demonstrated by the line, ABCD is the sum of the areas of two triangles: a right triangle ABD and a scalene triangle CDB.

We will determine the area of each triangle individually and then sum their values.

Right Triangle ABD:

We can use the above area formula if we know the angle between two sides.

Looking at our triangle, we know that ∠ADB is 55 DB is 10.

So, if we can find AD, we can apply the formula.

Notice that AD is the adjacent side to ∠ADB. Also, DB is the hypotenuse.

Since this is a right triangle, we can utilize the trig ratios.

In this case, we will use cosine. Remember that cosine is the ratio of the adjacent side to the hypotenuse.

Therefore:

\displaystyle \cos(55)=\frac{AD}{10}

Solve for AD:

AD=10\cos(55)

Now, we can use the formula. We have:

\displaystyle A=\frac{1}{2}ab\sin(C)

Substituting AD for a, 10 for b, and 55 for C, we get:

\displaystyle A=\frac{1}{2}(10\cos(55))(10)\sin(55)

Simplify. Therefore, the area of the right triangle is:

A=50\cos(55)\sin(55)

We will not evaluate this, as we do not want inaccuracies in our final answer.

Scalene Triangle CDB:

We will use the same tactic as above.

We see that if we can determine CD, we can use our area formula.

First, we can determine ∠C. Since the interior angles sum to 180 in a triangle, this means that:

\begin{aligned}m \angle C+44+38&=180 \\m\angle C+82&=180 \\ m\angle C&=98\end{aligned}

Notice that we know the angle opposite to CD.

And, ∠C is opposite to BD, which measures 10.

Therefore, we can use the Law of Sines to determine CD:

\displaystyle \frac{\sin(A)}{a}=\frac{\sin(B)}{b}

Where A and B are the angles opposite to its respective sides.

So, we can substitute 98 for A, 10 for a, 38 for B, and CD for b. Therefore:

\displaystyle \frac{\sin(98)}{10}=\frac{\sin(38)}{CD}

Solve for CD. Cross-multiply:

CD\sin(98)=10\sin(38)

Divide both sides by sin(98). Hence:

\displaystyle CD=\frac{10\sin(38)}{\sin(98)}

Therefore, we can now use our area formula:

\displaystyle A=\frac{1}{2}ab\sin(C)

We will substitute 10 for a, CD for b, and 44 for C. Hence:

\displaystyle A=\frac{1}{2}(10)(\frac{10\sin(38)}{\sin(98)})\sin(44)

Simplify. So, the area of the scalene triangle is:

\displaystyle A=\frac{50\sin(38)\sin(44)}{\sin(98)}

Therefore, our total area will be given by:

\displaystyle A_{\text{Total}}=50\cos(55)\sin(55)+\frac{50\sin(38)\sin(44)}{\sin(98)}

Approximate. Use a calculator. Thus:

\displaystyle A_{\text{Total}}\approx45.0861\approx45.1

8 0
3 years ago
Find the length of a side of an equilateral triangle given its altitude is six inches long.
vampirchik [111]
An equilateral triangle has three 60 degree angles.
The altitude divides it into two 30 60 90 triangles.
The altitude is the "middle side" of such a triangle.
When that is the case, the middle side divided by the square root of 3 = the short side and multiplied by (2/sq root (3)) equals the hypotenuse.
The hypotenuse is the side of the equilateral triangle. 
So, 6 * 2 / (sq root of 3) = <span> <span> <span> 6.9282032303 </span> </span> </span>

Source:
http://www.1728.org/trig2.htm


8 0
3 years ago
Thanks in advance for your help, the question is;
valkas [14]

Answer:

8, 9

Step-by-step explanation:

1/2x + 2(x + 1) = 22

1/2x + 2x + 2 = 22

1/2x + 2x = 20

5/2x = 20

5x = 40

x = 8

8, 9

4 + 18 = 22

5 0
3 years ago
Read 2 more answers
What is the positive solution to the equation:
Sindrei [870]

Answer:

x=8 or -8

Step-by-step explanation:

64 squared = 8 or -8

8x8=64

-8x-8 = 64

8 0
2 years ago
Read 2 more answers
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