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3 years ago

PLEASE HELP!!! A) 1 B) 2 C) 6 D) 10 E) 14

Mathematics

1 answer:

trapecia [35]3 years ago

8 0

Melinda is saving at the rate of 60/5 = $12 per week
Marcus is saving $14 per week

Difference is $2

Melinda is savinf $2 less than marcus each week

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7. What is the slope of the line that passes through (12, 10) and (11, 15)?

amid [387]

Answer:

-5

Step-by-step explanation:

5 0

3 years ago

Can someone solve for x please:

Alecsey [184]

THe LCD is x(x^2 - 4)

so multiplying through by this we get:-

2x(x + 2) + 7x = 5(x^2 - 4)
2x^2 + 4x + 7x = 5x^2 - 20
3x^2 - 11x - 20 = 0

(3x + 4)(x - 5 ) = 0

so x = 5 , -4/3

Its the second choice

3 0

3 years ago

Read 2 more answers

In 15–20, write the number positioned at each point.

Mumz [18]

Answer:

See below.

Step-by-step explanation:

15.) -3.25

16.) -4.5

17.) 1.25

18.) -5.75

19.) 0.5

20.) -2.5

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3 years ago

Assume the readings on thermometers are normally distributed with a mean of 0degreesc and a standard deviation of 1.00degreesc.

Tanzania [10]

Let Z be the reading on thermometer. Z follows Standard Normal distribution with mean μ =0 and standard deviation σ=1

The probability that randomly selected thermometer reads greater than 2.07 is

P(z > 2.07) = 1 -P(z < 2.07)

Using z score table to find probability below z=2.07

P(Z < 2.07) = 0.9808

P(z > 2.07) = 1- 0.9808

P(z > 2.07) = 0.0192

The probability that a randomly selected thermometer reads greater than 2.07 is 0.0192

3 0

3 years ago

the weight M of an object on Mars varies directly as it’s weight E on Earth. A person who weighs 95 lb on Earth weighs 38 lb on

lorasvet [3.4K]

Answer:

A 100 lb person will weight 40 lb on Mars

Step-by-step explanation:

Given:

Weight on Mars directly varies as its weight on earth.

Let weight on Mars be = $M$

Let weight on Earth be = $E$

Its known that:

$M$ ∝ $E$

Thus

$M=kE$

where $k$ is constant of proportionality.

when $E=95\ lb$ , then $M=38\ lb$

thus, we have

$38=k(95)$

dividing both sides by 95.

$\frac{38}{95}=\frac{k(95)}{95}$

∴ $k=\frac{38}{95}$

Thus when $E= 100$ , $M$ would be calculated as

$M=\frac{38}{95}\times 100$

$M=\frac{3800}{95}$

∴ $M=40\ lb$ (Answer)

∴ A 100 lb person will weight 40 lb on Mars.

8 0

3 years ago