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stealth61 [152]
3 years ago
6

Rewrite the linear equation y = 3x+19 in standard form.

Mathematics
1 answer:
BigorU [14]3 years ago
5 0

Answer:

3^x=9^{x+5}

Step-by-step explanation:

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I need help with both
uranmaximum [27]

Answer:

Part 1: 114,570,685 people

Part 2: The population grew by 2.5% (1,722,862 people)

Step-by-step explanation:  For part 1 you would multiply 100,236,820 by 1.143 because of the fact that your percentage is increasing.  so the 1 before the decimal point stands for 100% of the starting number and the .143 stands for the 14.3% that the population is increasing by.  


Part 2 you would divide 53,594,378 by 55,317,240 to get approximately .975.  .975 shows that 53,594,378 is about 97.5% of 55,317,240.  You then subtract the numbers 100 and 97.5 to get 2.5.  2.5 is the percentage that the population is increasing by.  So, then you could just subtract 55,317,240 and 53,594,378 to get 1,722,862.  This is the amount of people the population increased by.  Then you just put your answer that the population increased.  That it increased by 2.5% and 2.5%= 1,722,862 people

I hope this helps you :)

7 0
3 years ago
Find the values for a, b, and c that complete the simplification.
lisov135 [29]

Answer: A: 6

B: 4

C: 2

Step-by-step explanation:

8 0
3 years ago
Select the correct answer from each drop-down menu.
podryga [215]

Answer with explanation:

\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}

Average Height of tallest Building in San Francisco

                    =\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8

Average Height of tallest Building in Los Angeles

                    =\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9

→→Difference between Height of tallest Building in Los Angeles and  Height of tallest Building in San Francisco

               =233.9-197.8

               =36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

 |260-197.8|=62.2

 |237-197.8|=39.2

 |212-197.8|=14.2

 |197 -197.8|= 0.8

 |184 -197.8|=13.8

 |183-197.8|=14.8

 |183-197.8|= 14.8

 |175-197.8|=22.8

 |174-197.8|=23.8

 |173 -197.8|=24.8

Average of these numbers

     =\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12

Mean absolute deviation=23.12

5 0
3 years ago
If xy + y² = 6, then the value of dy/dx at x= -1 is<br>​
mylen [45]

Hi there!

\large\boxed{\text{At (-1, -2), }\frac{dy}{dx} = -\frac{2}{5}}}

\large\boxed{\text{At (-1, 3), }\frac{dy}{dx} = -\frac{3}{5}}}

We can calculate dy/dx using implicit differentiation:

xy + y² = 6

Differentiate both sides. Remember to use the Product Rule for the "xy" term:

(1)y + x(dy/dx)  + 2y(dy/dx) = 0

Move y to the opposite side:

x(dy/dx) + 2y(dy/dx) = -y

Factor out dy/dx:

dy/dx(x + 2y) = -y

Divide both sides by x + 2y:

dy/dx = -y/x + 2y

We need both x and y to find dy/dx, so plug in the given value of x into the original equation:

-1(y) + y² = 6

-y + y² = 6

y² - y - 6 = 0

(y - 3)(y + 2) = 0

Thus, y = -2 and 3.

We can calculate dy/dx at each point:

At y = -2: dy/dx = -(-2) / -1+ 2(-2) = -2/5.

At y = 3: dy/dx = -(3) / -1 + 2(3) = -3/5.

5 0
3 years ago
Can someone answer this? Thanks a lot
Komok [63]

Answer:

Step-by-step explanation:

Use math-way go quick and easy answers without step by step explanations, and use math-soup-calculator for step by step explanation

3 0
3 years ago
Read 2 more answers
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