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Travka [436]
3 years ago
11

The areas of the squares adjacent to two sides of a right triangle are 29.2529.2529, point, 25 units^2 2 squared and 131313 unit

s^2 2 squared. Find the length, xxx, of the third side of the triangle.
Mathematics
2 answers:
Morgarella [4.7K]3 years ago
6 0

Answer:

It is 6.5 units

bonufazy [111]3 years ago
3 0

Answer:

6.5 units

Step-by-step explanation:

We are given that

Two adjacent sides of right triangle

Suppose a,b and c are sides of right triangle.

a^2=29.25squared units

b^2=13square units.

Length of third side,c=x units

We have to find the length of third side of the triangle.

x^2=a^2+b^2

By using Pythagoras theorem

(Hypotenuse)^2=(Perpendicular\;side)^2+(Base)^2

x^2=29.25+13

x=\sqrt{29.25+13}

x=6.5units

Hence, the length x of the third side of the triangle=6.5 units

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What is the distance between the points (2,10) and (-6, 4) on the coordinate
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Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate  plane is 10units

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Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} units

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Now substituting the values in the distance formula  we get

s=\sqrt{(-6-2)^2+(4-10)^2}

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5 0
4 years ago
4. A number m is such that when it is divided by 30, 36, and 45 the remainder is always 7,
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Answer:

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Step-by-step explanation:

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But we need a number that leaves a remainder of 7 so we add 7 to 180 to get; 180 + 7 = 187.

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