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Vinvika [58]
3 years ago
13

Please help me find the median to this table

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

The median is 19.45

Step-by-step explanation:

Organize the numbers from least to greatest

16.3, 17.8, 17.8, 18.0, 18.7, 19.3, 19.6, 20.1, 20.5, 21.9, 25.2, 25.4

Find the middle of the set of numbers

19.3 and 19.6

Add 9.3 and 19.6

19.3 + 19.6=

38.9

Divide by 2

38.9/2

Which is 19.45

Hope this helps

You might be interested in
S
Novay_Z [31]

Step-by-step explanation:

s is inversely proportional to t

If s= 0.6 , t= 4

s=k/t

0.6= k/4

k=2.4

If s=12, then

t=k/s

t=2.4/12

t=0.05

8 0
3 years ago
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Hailey cuts a 7-inch square piece of plywood for a birdhouse. She rotates the piece 90° counterclockwise. What is the length in
Readme [11.4K]

Answer:

\huge\boxed{7\  \text{inches}}

Step-by-step explanation:

As I mentioned earlier with a single side (line), rotations do not change the size of something. Only dilations do that. This goes for both lines AND shapes.

However, if the question said she dilated the piece, then yes, the length in inches would be different. However, rotation just changes the position and nothing happens to the length.

Hope this helped!

3 0
4 years ago
What does an S-shaped curve for population growth suggest?
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A pattern of growth<span> in which, in a new environment, the </span>population<span> density of an organism increases slowly initially, in a positive acceleration phase; then increases rapidly, approaching an exponential </span>growth<span> rate</span>
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