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arsen [322]
3 years ago
5

How do you do this problem? See attached image

Mathematics
2 answers:
Leokris [45]3 years ago
7 0

Answer:

I think the answer is d

Step-by-step explanation: you have to divide both sides by 6

please mark as brainliest

never [62]3 years ago
5 0
Divide both sides by -6.
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Explain please, I’ve been having trouble with this question
GuDViN [60]

Step-by-step explanation:

I didn't need the other angles, but right of the bat you can tell it's two right triangles back to back.

<em>y </em> has to be 90° , as you have noticed they already gave you 70° on the right side of the shape meaning if you were to add 90 which is why plus 70 what would that give you? 160.

the total interior for a triangles angles has to be 180°. if you do the math 180 - 160 you get the leftover 20° for x.

I suck at explaining stuff, hope this helps

7 0
2 years ago
I need help with this because this is hard
SOVA2 [1]
V=8, did it on equations solver
3 0
2 years ago
Read 2 more answers
What is the common ratio for the geometric sequence?<br><br> 18, 12, 8, 16/3,…
alex41 [277]

Answer:

2/3

Step-by-step explanation:

Given : A geometric sequence : 18, 12, 8, 16/3,…

Solution :

Each term is found by multiplying the previous term by a constant in a Geometric Sequence .

In a Geometric Sequence  common ratio is denoted by r


r = \frac{a_{n} }{a_{n-1} }


for n = 2


r = \frac{a_{2} }{a_{1} }


⇒r = \frac{12 }{18 }


⇒r = \frac{2 }{3 }


for n = 3


r = \frac{a_{3} }{a_{2} }


⇒r = \frac{8 }{12 }


⇒r = \frac{4 }{6 }


⇒r = \frac{2}{3 }


Thus the common ratio 'r' = 2/3

6 0
3 years ago
Read 2 more answers
Evaluate using the given values<br> b=1, c=2, d=3, p=-3, q=-2, r=-1<br> a) 2b+c-d
IRISSAK [1]
The answer should be one
5 0
3 years ago
From the top of a vertical cliff 50 m high, the angle of depression of an object that is level with the base of the cliff is 70°
Svetlanka [38]

Answer:

The distance of the object from the base of cliff is 18.24 meters

Step-by-step explanation:

Given as :

The height of the vertical cliff = h = 50 meters

The distance of the object from the base of cliff = x meters

Let The angle of depression of object that level with cliff base = Ф = 70°

<u>Now, from figure</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

I.e TanФ = \dfrac{\textrm AB}{\textrm OA}

Or, TanФ = \dfrac{\textrm h}{\textrm x}

Or, Tan 70° = \dfrac{\textrm 50 meters}{\textrm x meters}

Or, 2.74 = \dfrac{\textrm 50}{\textrm x}

∴ x =  \dfrac{\textrm 50}{\textrm 2.74}

I,e x = 18.24 meters

So, The distance of the object from the base of cliff = x = 18.24 meters

Hence,The distance of the object from the base of cliff is 18.24 meters Answer

5 0
3 years ago
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