Suppose that the log-ons to a computer network follow a Poisson process with an average of 3 counts per minute. (a) What is the
1 answer:
Answer: a) 0.333, b) 0.333 and c) 0.9986.
Step-by-step explanation:
Since we have given that
Average = 3 counts per minute = λ
a) What is the mean time between counts ?
Since it follows a Poisson Process, So,
(b) What is the standard deviation between counts ?
(c) If it is an average of 3 counts per minute, find the value of such that .
If the average = 3 counts per minute.
Then,
Hence, a) 0.333, b) 0.333 and c) 0.9986.
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I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus
Answer:
Check the explanation
Step-by-step explanation:
where the letter D is the diagonal matrix with diagonal entries λ1,…,λn. Now let's assume V is invertible, that is, this particular given eigenvectors are linearly independent, you get M=VDV−1.
Kindly check the attached image below to see the step by step explanation to the question above.
