Partitioning the interval
![[6,11]](https://tex.z-dn.net/?f=%5B6%2C11%5D)
into

equally-spaced subintervals gives

rectangles of width

and of heights determined by the right endpoints of each subinterval.
If

, then

,

, and so on, up to

. Because we're using the right endpoints, the approximation will consider

The definite integral is then approximated by

You have




To check that this is correct, let's make sure the sum converges to the exact value of the definite integral. As

, you have the sum converging to

.
Meanwhile,
![\int_6^{11}(1-5x)\,\mathrm dx=\left[x-\dfrac52x^2\right]_{x=6}^{x=11}=-\dfrac{415}2](https://tex.z-dn.net/?f=%5Cint_6%5E%7B11%7D%281-5x%29%5C%2C%5Cmathrm%20dx%3D%5Cleft%5Bx-%5Cdfrac52x%5E2%5Cright%5D_%7Bx%3D6%7D%5E%7Bx%3D11%7D%3D-%5Cdfrac%7B415%7D2)
so we're done.
The answer is 40 as -2*-2*-2=-8 after multiply by -5=40
Answer:
B
Step-by-step explanation:
Given
y = f(x), then
y = f(x ± a) is a horizontal translation of a units
• If f(x + a) then shift of a units left ←
• If f(x - a) then shift of a units right →
A) (2, 7) (0, 3)
B) (1,5) (3, 3)
C) inconsistent because it starts to go down.
D) (0,3) (1, 5) (2,7) (3,3)
I hope this helped