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Goshia [24]
2 years ago
7

Please help i don't know what I'm doing ​

Mathematics
2 answers:
gulaghasi [49]2 years ago
8 0

Answer:

11 is the answer

Step-by-step explanation:

prisoha [69]2 years ago
5 0

Answer:

11

Step-by-step explanation:

to find one of the addend

subtract another one of the addend by the sum

eg : 9 + __= 20

20 - 9 = 11

now we can check

9 + 11 = 20

hope this helps

thanks bye

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Square is 19 yd.² what is the length of each side
olga_2 [115]
the answer is 4.36yds. 4.36 ×4.36= 19.006
6 0
3 years ago
15 points: can someone help me with this thank you. (all separate equations)
OLga [1]

Step-by-step explanation:

6x+3y=12\qquad\text{subtract}\ 6x\ \text{from both sides}\\\\6x-6x+3y=12-6x\\\\3y=12-6x\qquad\text{divide both sides by 3}\\\\\dfrac{3y}{3}=\dfrac{12}{3}-\dfrac{6y}{3}\\\\\large\boxed{y=4-2y}\\\\===================

2p-k=3\qquad\text{subtract}\ 2p\ \text{from both sides}\\\\2p-2p-k=3-2p\\\\-k=3-2p\qquad\text{change the signs}\\\\k=-3+2p\\\\\large\boxed{k=2p-3}\\\\===================

6v-2w=10\qquad\text{subtract}\ 6v\ \text{from both sides}\\\\6v-6v-2w=10\\\\-2w=10-6v\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2w}{-2}=\dfrac{10}{-2}-\dfrac{6v}{-2}\\\\w=-5+3v\\\\\large\boxed{w=3v-5}\\\\===================

5 0
3 years ago
There are 9 performers who are to present their acts at a variety show. How many different ways are there to schedule their appe
nika2105 [10]
For this type of question it is easiest to think about it in terms of a simple multiplication. The way we can do this is by working out how many possibilities there are for each position on the program. This is as follows:
For the first act, there are 9 possible performers we can pick
For the second act, because we have already assigned a performer to the first act, there are only 8 possible performers
For the third act, because we have already assigned a performer to the first two acts, there are only 7 possible performers
This goes on and on until we reach the final act, where we have used all the performers except one.
Therefore we can say:
For the first act there are 9 possibilities
For the second act there are 8 possibilities
For the third act there are 7 possibilities
For the fourth act there are 6 possibilities and so on
If we want to write this mathematically we can just say that there are:
9 possibilities x 8 possibilites x 7 possibilities etc right down until we are at the final act where there is 1 possibility.
To write this out as an equation we just say:
9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = the number of different ways
In maths however, we have a much simpler way of saying this, which we call "factorial".
That whole stream of numbers up there can just be said to be "9 factorial", or if we are writing it in an equation "9!". You may find that your calculator has a button which has an "!" on it. If you put in the number of performers and then press the "!" button, it will give you the answer to your question.
Hope this helped you :)
3 0
3 years ago
A pizza restaurant offers the following deals
Elanso [62]

Answer:

Step-by-step explanation:

Deal #1: One pizza= $8.99  

Deal #2: One pizza= $6.00  

Deal #1: Two pizzas= $13.99  

Deal #2: Two pizzas= $12.00  

Deal #1: Three pizzas= $18.99  

Deal #2: Three pizzas= $18.00  

Deal #1: Four pizzas= $23.99  

Deal #2: Four pizzas= $24.00  

Therefore, after FOUR pizzas, deal #1 becomes a better deal.  

Tip: Practice some math. You should be able to answer something like this within two minutes MAXIMUM.

4 0
3 years ago
Suppose we have four integers, no two of which are congruent $\pmod 6$. Let $N$ be the product of the four integers. If $N$ is n
aalyn [17]

Answer:

4

Step-by-step explanation:

Given:

A, B, C, D have distinct positive values for mod 6

A (mod 6) = 1

B (mod 6) = 2

C (mod 6) = 4

D (mod 6) = 5

Each mod 6 value cannot be a zero since the product ABCD is not a multiple of 6.

Furthermore, in order that ABCD mod 6 > 0, we cannot  have a residue equal to 3, else the product with a residue 2 or 4 will make the product a multiple of 6.

Thus the only positive residues can only be 1,2,4,5

A*B*C*D  (mod 6) > 0  = 1*2*4*5 (mod 6) = 4

4 0
3 years ago
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