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ryzh [129]
3 years ago
9

How would I solve this system of equations? 2y+x=-17 5x-4y=-15

Mathematics
1 answer:
Ratling [72]3 years ago
3 0

\left\{\begin{array}{ccc}2y+x=-17\\5x-4y=-15\end{array}\right\\\\\left\{\begin{array}{ccc}x+2y=-17&\text{multiply both sides by 2}\\5x-4y=-15\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}2x+4y=-34\\5x-4y=-15\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad7x=-49\qquad\text{divide both sides by 7}\\.\qquad\boxed{x=-7}\\\\\text{Put the value of x to the first equation:}\\\\2y+(-7)=-17\\2y-7=-17\qquad\text{add 7 to both sides}\\2y=-10\qquad\text{divide both sides by 2}\\\boxed{y=-5}\\\\Answer:\ \boxed{x=-7\ and\ y=-5\to(-7,\ -5)}

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Answer:

One solution                    

Step-by-step explanation:

5x + y = 8

15x + 15y = 14

Lets solve using substitution, first we need to turn "5x + = 8" into "y = mx + b" or slope - intercept form

So we solve for "y" in the equation "5x + y = 8"

5x + y = 8

Step 1: Subtract 5x from both sides.

5x + y − 5x = 8 − 5x

Step 2: 5x subtracted by 5x cancel out and "8 - 5x" are flipped

y = −5x + 8

Now we can solve using substitution:

We substitute "-5x + 8" into the equation "15x + 15y = 14" for y

So it would look like this:

15x + 15(-5x + 8) = 14

Now we just solve for x

15x + (15)(−5x) + (15)(8) = 14(Distribute)

15x − 75x + 120 = 14

(15x − 75x) + (120) = 14(Combine Like Terms)

−60x + 120 = 14

Step 2: Subtract 120 from both sides.

−60x + 120 − 120 = 14 − 120

−60x = −106

Divide both sides by -60

\dfrac{ -60x  }{ -60  }   =   \dfrac{ -106  }{ -60  }

Simplify

x =   \dfrac{ 53  }{ 30  }

Now that we know the value of x, we can solve for y in any of the equations, but let's use the equation "y = −5x + 8"

\mathrm{So\:it\:would\:look\:like\:this:\ y =  -5 \left(  \dfrac{ 53  }{ 30  }    \right)  +8}

\mathrm{Now\:lets\:solve\:for\:"y"\:then}

y =  -5 \left(  \dfrac{ 53  }{ 30  }    \right)  +8}

\mathrm{Express\: -5 \times   \dfrac{ 53  }{ 30  }\:as\:a\:single\:fraction}

y =   \dfrac{ -5 \times  53  }{ 30  }  +8

\mathrm{Multiply\:-5 \:and\:53\:to\:get\:-265 }

y =   \dfrac{ -265  }{ 30  }  +8

\mathrm{Simplify\:  \dfrac{ -265  }{ 30  }    \:,by\:dividing\:both\:-265\:and\:30\:by\:5} }

y =   \dfrac{ -265 \div  5  }{ 30 \div  5  }  +8

\mathrm{Simplify}

y =  - \dfrac{ 53  }{ 6  }  +8

\mathrm{Turn\:8\:into\:a\:fraction\:that\:has\:the\:same\:denominator\:as\: - \dfrac{ 53  }{ 6  }}

\mathrm{Multiples\:of\:1: \:1,2,3,4,5,6}

\mathrm{Multiples\:of\:6: \:6,12,18,24,30,36,42,48}

\mathrm{Convert\:8\:to\:fraction\:\dfrac{ 48  }{ 6  }}

y =  - \dfrac{ 53  }{ 6  }  + \dfrac{ 48  }{ 6  }

\mathrm{Since\: - \dfrac{ 53  }{ 6  }\:have\:the\:same\:denominator\:,\:add\:them\:by\:adding\:their\:numerators}

y =   \dfrac{ -53+48  }{ 6  }

\mathrm{Add\: -53 \: and\: 48\: to\: get\:  -5}

y =  - \dfrac{ 5  }{ 6  }

\mathrm{The\:solution\:is\:the\:ordered\:pair\:(\dfrac{ 53  }{ 30  }, - \dfrac{ 5  }{ 6  })}

So there is only one solution to the equation.

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Answer:

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Carl and Rose' balconies make up the base of an isosceles triangle.

Their distances from the flagpole is the same.

From the question, we understand that:

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The above highlights mean that:

The relationship between Carl and Rose' balconies and the flagpole is an isosceles triangle.

Where Carl and Rose' balconies form the base of the isosceles triangle.

Hence, their distances from the flagpole is the same.

Read more about distances at:

brainly.com/question/12961022

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