Answer:
landslide
This is so easy you can answer this if you study and cheat on class
The right answer is C.
A genetic disease is called autosomal dominant transmission when
:
* The morbid allele ("sick" version, mutated of the gene in question) is on a non-sexual chromosome (neither X nor Y).
* The presence of a single morbid allele is sufficient for the disease to express itself.
The morbid allele is transmitted by either the father or the mother (or both, if they have the same inherited autosomal dominant genetic disease). Anyone with one of their affected parents is affected.
Jackson-Weiss syndrome is indeed an autosomal dominant disease characterized by a malformation of the feet, craniosynostosis of varying degrees, facial abnormalities, enlargement of the big toes and normal hands.
I believe it is B but I’m not 100% sure
Answer:
The answer is the third option; all the pea plants with green seeds contain same alleles for that trait.
Explanation:
This question shows a monohybrid cross involving a single gene coding for seed colour in pea plant. Two traits controlled by two alleles are involved viz: Yellow allele (Y) coding for yellow trait and green allele (y) coding for green trait. Two purebreeding parents are crossed in the P generation i.e. YY (yellow pea) × yy (green pea).
Based on the image, all the F1 offsprings exhibited yellow seeds meaning that the allele for yellow seed color (Y) is dominant over the allele for green seed color (y). Two heterozygous F1 offsprings (Yy) are self-crossed to give an F2 offsprings in a ratio 3 Yellow : 1 green.
Using a punnet square, a Yy × Yy cross in the F1 generation will give rise to four offsprings with genotypes: YY, Yy, Yy and yy.
YY, Yy and Yy are yellow offsprings while yy is a green offspring.
Based on this, all the pea plants with green seeds in the F2 generation contained the same alleles (yy) for the trait.
