Answer:
The prices of the two stocks be the same after 2.88 hours after 12 pm
Step-by-step explanation:
Price of stock A at 9 a.m.= $13.56
The price has been increasing at the rate of $0.12 each hour.
Increase in price after 3 hours =![0.12 \times 3 =0.36](https://tex.z-dn.net/?f=0.12%20%5Ctimes%203%20%3D0.36)
Price of Stock A at noon= 13.56+0.36 = $13.92
Let n be the no. of hours after which the prices of both the stocks will be same .
So, Increase in price after n hours = 0.12 n
Price of Stock A after n hours = 13.92+0.12 n
Price of stock B = $14.31
The price has been decreasing at the rate of $0.14 each hour.
Let n be the no. of hours
So, Increase in price after n hours = 0.14 n
Price of Stock B after n hours =14.31-0.14 n
ATQ
![13.56+0.12 n= 14.31-0.14 n](https://tex.z-dn.net/?f=13.56%2B0.12%20n%3D%2014.31-0.14%20n%20)
![-13.56+14.31=0.14 n + 0.12 n](https://tex.z-dn.net/?f=-13.56%2B14.31%3D0.14%20n%20%2B%200.12%20n%20)
![0.75=0.26 n](https://tex.z-dn.net/?f=0.75%3D0.26%20n)
![\frac{0.75}{0.26}=n](https://tex.z-dn.net/?f=%5Cfrac%7B0.75%7D%7B0.26%7D%3Dn)
![2.88=n](https://tex.z-dn.net/?f=2.88%3Dn)
Hence the prices of the two stocks be the same after 2.88 hours after 12 pm .