A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter
her second litter had 3 more pups than her first.( first litter +3)=2nd litter
Find the number of pups in her litter
Pretty sure it's 0, if you mean 2 to the power of 0
Answer:
the answer is 18
Step-by-step explanation:
Answer:
Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.
Step-by-step explanation:
✔️Function A:
Initial value = y-intercept (b)
y-intercept is the value of y, when the corresponding value of x = 0
From the table, y = 6 when x = 0.
The y-intercept of function A = 6
Therefore, initial value for Function A = 6
✔️Function B:
y = 4x + 3 is given in the slope-intercept form, y = mx + b.
b = y-intercept = initial value.
Therefore
Initial value for Function B = 3
✔️Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.
Answer: D. (4,3)
The x coordinates of A and B are 9 and -1 in that order. Add them up to get 9+(-1) = 9-1 = 8. Then divide by two to end up with 8/2 = 4. The midpoint has an x coordinate of 4.
Repeat for the y coordinates. Add them up: 8+(-2) = 8-2 = 6. Then divide by two: 6/2 = 3. The midpoint has an y coordinate of 3.
Those two coordinates pair up to get (x,y) = (4,3) which is the midpoint of segment AB.
