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1 answer:
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5x = y + 6 (I)
2x - 3y = 4 (II)
-------------------
We have:
5x = y + 6 →
Soon:
2x - 3y = 4 →
<span>least common multiple (5)
</span>
2x - 3y = 4 (II)
-------------------
We have:
5x = y + 6 →
Soon:
2x - 3y = 4 →
<span>least common multiple (5)
</span>
Answer:
Assuming the area is made up of a square and a semicircle.
<u>Perimeter</u>
The side length of the square = 18 ft
We can see 3 full side lengths plus one side length from which we need to subtract 12 ft (see attached diagram).
⇒ perimeter of the square = (3 x 18) + (18 - 12)
= 54 + 6
= 60 ft
Circumference of a circle = d (where d is the diameter)
⇒ arc length of the semicircle = 1/2 circumference
= 1/2 · · 12
= 6 ft
Total perimeter = 60 + 6 = 78.8 ft (nearest tenth)
<u>Area</u>
Area of a square = s² (where s is the side length)
⇒ area of square = 18²
= 324 ft²
Diameter = 2r ⇒ r = 1/2 diameter
Area of a circle = r² (where r is the radius)
⇒ area of the semicircle = 1/2 · · 6²
= 18 ft²
Total area = 324 + 18 = 380.5 ft² (nearest tenth)
Answer:
The interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.
Step-by-step explanation:
In statistics, the 68–95–99.7 rule, also recognized as the Empirical rule, is a shortcut used to recall that 68%, 95% and 99.7% of the values lie within one, two and three standard deviations of the mean, respectively.
Then,
- P (µ - σ < X < µ + σ) = 0.68
- P (µ - 2σ < X < µ + 2σ) = 0.95
- P (µ - 3σ < X < µ + 3σ) = 0.997
he random variable <em>X</em> can be defined as the amount of time a certain brand of light bulb lasts.
The random variable <em>X</em> is normally distributed with parameters <em>µ</em> = 1300 hours and <em>σ</em> = 90 hours.
Compute the interval of hours that represents the lifespan of the middle 68% of light bulbs as follows:
Thus, the interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.