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pentagon [3]
3 years ago
10

Describe how the shape moves to get from its position in each frame to the next.

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
6 0

Answer:

reflection

Step-by-step explanation:

from 1 to 2 it is reflection across the y-axis and from 2 to three it is reflection across the x-axis then 3 to 4 it is reflected across the y-axis again and then from 4 to 5 it is reflected across the x-axis.

gogolik [260]3 years ago
4 0

Answer:

It's reflection

Step-by-step explanation:

Reflection THANKS!

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A sphere and a right cylinder have the same radius and volume. The cylinder has a height of 8 feet. Find the radius.
siniylev [52]

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Answer:

  6 feet

Step-by-step explanation:

The volume of a cylinder is given by ...

  V = πr^2·h

For a sphere, the volume is ...

  V = 4/3πr^3

You want the volumes to be the same when h=8, so we have ...

  πr^2·8 = 4/3πr^3

Dividing by πr^2, we have ...

  8 = 4/3r

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The radius is 6 feet.

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Owen is 147.3 cm tall
melomori [17]
Owen is aroumd 4.87 feet tall also.
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3 years ago
If ​f(x)equals 2xminus5 and ​k(x)equals ​f(xplus3​), write the equation for​ k(x).
ololo11 [35]
F(x)=2x-5
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3 years ago
If 24 pieces of velcro costs 1.95 how much would 1000 pieces cost
BartSMP [9]
Hi!

Each piece cost 1.95, then 1000 pieces will cost:

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2 years ago
Assume that f is continuous on [-4,4] and differentiable on (-4,4). The table gives some values of f'(x) x: -4, -3, -2, -1, 0, 1
kondaur [170]
f will be increasing on the intervals where f'(x)>0 and decreasing wherever f'(x). Local extrema occur when f'(x)=0 and the sign of f'(x) changes to either side of that point.

f'(x) is positive when x is between -4 and some number between -2 and -1, and also 2 (exclusive) and 4, so you can estimate that f(x) is increasing on the intervals [-4, -2] and (2, 4].

f'(x) is negative when x is between some number between -2 and -1, up to some number less than 2. So f(x) is decreasing on the interval [-1, 1].

You then have two possible cases for extrema occurring. The sign of f'(x) changes for some x between -2 and -1, and again to either side of x=2.
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3 years ago
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