Suppose you pull a shirt from the dryer. It has a sock stuck to it. Explain why this happens.

A silver block, initially at 57.2 ∘C, is submerged into 100.0 g of water at 24.8 ∘C, in an insulated container. The final temper

Masteriza [31]

Answer:

96.5 grams is the mass of the silver block.

Explanation:

Heat lost by iron will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of iron = $m_1=?$

Specific heat capacity of silver= $c_1=0.240 J/g^oC$

Initial temperature of the silver= $T_1=120^oC$

Final temperature = $T_2=T=26.5^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=100.0 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=24.8 ^oC$

Final temperature of water = $T_2=T=26.5^oC$

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(m_1\times 0.240 J/g^oC\times (26.5^oC-57.2^oC))=100.0 g\times 4.184 J/g^oC\times (26.5^oC-24.8^oC)$

we get, $m_1 = 96.5 g$

96.5 grams is the mass of the silver block.

5 0

4 years ago

Stella has poured 3 cups of water into a 1-L soda bottle. Stella then sealed the bottle and placed it in the sunlight. What natu

san4es73 [151]

The answer is D. The Water Cycle

7 0

3 years ago

Read 2 more answers

Can someone please help me?

Olin [163]

Answer:

c.)the reactants have the same mass as the products

Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

hope it helps!

8 0

3 years ago

How many elements are there?

svlad2 [7]

Answer:

118 is your answer!

5 0

3 years ago

Read 2 more answers

A mixture of 0.2000 mol of CO2, 0.1000 mol of H2 and 0.1600 mol of H2O is placed in a 2.000-L vessel. The following equilibrium

Slav-nsk [51]

Answer:

a) p(CO2) = 4.103 atm

p(H2) = 2.0515 atm

p(H2O) = 3.2824 atm

b) pCO2 = 3.8754 atm

pH2 = 1.8239 atm

pCO = 0.2276 atm

pH2O = 3.51 atm

c) Kp= 0.113

Explanation:

Step 1: Data given

Moles of CO2 = 0.2000 mol

Moles of H2 = 0.1000 mol

Moles of H2O = 0.1600 mol

Volume = 2.000 L

Temperature = 500 k

Step 2: The balanced equation

CO2 (g) + H2 (g) → CO (g) + H2O (g)

Step 3: Calculate the initial partial pressures of CO2, H2, and H2O.

pV = nRT

P = (nRT)/V

p(CO2) = (0.2000 mol * 0.08206 * 500)/2.000L

⇒ p(CO2) = 4.103 atm

p(H2) = (0.1000 mol * 0.08206 * 500)/2.000L

⇒ p(H2) = 2.0515 atm

p(H2O) = (0.1600 mol * 0.08206 * 500)/2.000L

⇒ p(H2O) = 3.2824 atm

b. At equilibrium PH2O= 3.51 atm. Calculate the equilibrium partial pressures of CO2, H2, and CO.

Step 1: Calculate the change in pH2O

The change in pH2O = 3.51 - 3.2824 = 0.2276

Step 2: the initial pressures

pCO2 = 4.103 atm

pH2 = 2.0515 atm

pCO = 0 atm

pH2O = 3.2824

Step 3: The partial pressure at the equilibrium

Since there reacts 0.2276 atm for H2O, and the mol ratio is 1:1:1:1

For each gas, there will react 0.2276 atm

pCO2 = 4.103 - 0.2276 = 3.8754 atm

pH2 = 2.0515 - 0.2276 = 1.8239 atm

pCO = 0 + 0.2276 = 0.2276 atm

pH2O = 3.51 atm

c. Calculate Kp for this reaction

Kp = (pCO * pH2O)/ (pCO2 * pH2)

Kp = (0.2276 * 3.51) /( 3.8754 *1.8239)

Kp = 0.113

5 0

3 years ago