Question

2. A gas that occupies a volume of 6.75 L at 89.0 atm will occupy what volume at 68.55 mm Hg if the temperature remains constant?

Answer 1

First convert pressure to atm

• 1atm=760mm hg
• 68.55 mm Hg= 0.09atm

Now

• V1=6.75L
• V2=?
• P1=89atm
• P2=0.09atm

Apply Boyle's law

$\\ \rm\Rrightarrow P1V1=P2V2$

$\\ \rm\Rrightarrow 89(6.75)=0.09V2$

$\\ \rm\Rrightarrow 600.75=0.09V2$

$\\ \rm\Rrightarrow V2=\dfrac{600.75}{0.09}$

$\\ \rm\Rrightarrow V2=6675L$