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3 years ago

Choose all that apply. The metric system includes units for measuring:

Chemistry

2 answers:

zalisa [80]3 years ago

3 0

Answer:

weight, length, speed

AfilCa [17]3 years ago

3 0

I know that one of the answers is weight

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Who know the answers for both of these or know were to get them from

pentagon [3]

Answer:

kdkekejdjejeneneenendjenejekeke do do do do do do d

8 0

2 years ago

Read 2 more answers

Identify the total number of moles involved in the reaction

raketka [301]

Answer:

33 moles

Explanation:

The given chemical reaction is 2C₄H₁₀(g) + 13 O₂(g) → 10H₂O(g) + 8CO₂(g)

The number of moles of each reactant are as follows;

Butane, C₄H₁₀ = 2 moles of (g) + 13 (g) → 10H₂O(g) + 8CO₂(g)

Oxygen gas, O₂ = 13 moles

Water, H₂O = 10 moles

Carbon dioxide, CO₂ = 8 moles

The total number of moles, n = (2 + 13 + 10 + 8) = 33

∴ The total number of moles involved in the reaction, n = 33 moles.

7 0

3 years ago

Which is the reason that ionic compounds are brittle? The bonds between the anions and cations are weak and therefore easily bro

bearhunter [10]

Well ionic compounds are brittle because similar charges repel, which causes them to break usually occurring when a force is applied, like a hammer strike.

8 1

3 years ago

A solution is made by dissolving 9.74 g of sodium sulfate in water to a final volume of 165 mL of solution. What is the weight/w

MatroZZZ [7]

Answer: The weight/weight % or percent by mass of the solute is 5.41 %.

Explanation:

Mass of the sodium sulfate,w = 9.74 g

Volume of the water = 165 mL

Density of the water = 1 g/mL

$Density=1 g/mL=\frac{\text{Mass of water}}{\text{Volume of water}}$

Mass of the water = $1 g/mL\times 165 mL=165 g$

Mass of the solution, W:

Mass of solute + Mass of solvent =9.47 g + 165 g=174.47 g

$w/w\%=\frac{w\times 100}{W}=\frac{9.45 g\times 100}{174.47 g}=5.41 \%$

The weight/weight % or percent by mass of the solute is 5.41 %.

8 0

3 years ago

Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit

vfiekz [6]

Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $H_2SO_4$ :-

Mass of $H_2SO_4$ = 196 g

Molar mass of $H_2SO_4$ = 98 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{196\ g}{98\ g/mol}$

$Moles\ of\ Sulfuric\ acid= 2\ mol$

According to the given reaction:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

<u>Mass = Moles*molar mass = $4\times 40\ g$ = 160 g</u>

7 0

2 years ago