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2 years ago

Calculate the molarity of a 10.0% (by mass) aqueous solution of hydrochloric acid.

Chemistry

1 answer:

olga2289 [7]2 years ago

6 0

The question is incomplete,the complete question :

Calculate the molality of a 10.0% (by mass) aqueous solution of hydrochloric acid:

a) 0.274 m

b) 2.74 m

c) 3.05 m

d) 4.33 m

e) the density of the solution is needed to solve the problem

Answer:

The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.

Explanation:

10.0% (by mass) aqueous solution of hydrochloric acid.

10 grams of HCl is present in 100 g of solution.

Mass of HCl = 10 g

Mass of solution = 100 g

Mass of solution = Mass of solute + Mass of water

Mass of water = 100 g - 10 g = 90 g

Moles of HCl = $\frac{10 g}{36.5 g/mol}=0.2740 mol$

Mass of water in kilograms = 0.090 kg

Molality = $\frac{0.2740 mol}{0.090 kg}=3.05 mol/kg$

The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.

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Which of these solutions is the most basic?

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<h2>Question↷</h2>

Which of these solutions is the most basic?

[OH-] = 4.3 x 10-9 M

[OH-] = 2.8 x 10-11 M

[OH-] = 6.7 x 10-10 M

[OH-] = 1.0 x 10-5 M

<h2>Answer↷</h2>

<u>[OH-] = 1.0 x 10-5 M</u> ✓

<h2>Solution↷</h2>

[OH-] = 4.3 x 10-9 M

[OH-] = 4.3 x 10^-9 M
pOH = - log [OH^1-]
pOH = - log [4.3 x 10^-9]
pOH = 8.36
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_______________________________________

[OH-] = 2.8 x 10-11 M

[OH-] = 2.8 x 10^-11 M
pOH = - log [OH^1-]
pOH = - log [2.8 x 10^-11 ]
pOH = 10.55
pH = 14-10.55
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_______________________________________

[OH-] = 6.7 x 10-10 M

[OH-] = 6.7 x 10^-10 M
pOH = - log [OH^1-]
pOH = - log [6.7 x 10^-10]
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pH = 14-9.17
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_______________________________________

[OH-] = 1.0 x 10-5 M

[OH-] = 1.0 x 10-5 M
pOH = - log [OH^1-]
pOH = - log [1.0 x 10^-5 ]
pOH = 5
pH = 14-5
pH = 9

_______________________________________

we know that , the solution with <u>pH > 7</u> is termed as basic and more the pH ,more the basicity, hence ,the solution with the highest pH would be the strongest base out of these all which is

<u>[OH-] = 1.0 x 10-5 M</u> with pH = 9

_______________________________________

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