Answer:
20
Step-by-step explanation:
A rectangle is 5 times as long as it is wide. The perimeter is 70 cm. Find the dimensions of the rectangle. Round to the nearest
1 answer:
You might be interested in
Answer: B. Jonesville is growing linearly and Smithville is growing exponentially.
Step-by-step explanation:
Linear growth :
- Population grow by a constant amount after each time period.
- The rate of change of dependent variable with respect to independent variable is a constant.
- It is represented by line on graph.
- Equation for linear growth :
, c = initial value and m is the rate of change of y with respect to x.
Exponential growth :
- Population grow by a constant ratio .
- It is represented by a curve on graph.
- Equation for exponential growth :
, a = initial value and r is rate of growth ( in decimal ) and x is time period.
Given : Jonesville's population grows by 170 people per year.
i.e .Population grow by a constant amount per year.
⇒ Jonesville is growing linearly.
The population of smithville grows by 7% per year.
i.e. Population grow by a constant ratio.
⇒Smithville is growing exponentially.
Hence, the true statement is "B. Jonesville is growing linearly and Smithville is growing exponentially."
That'd be true only if the value of "s" is the exact same one for both
namely if sec(s) = cos(s)
then solving for "s"
thus
![\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)} \\\\\\ thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s) \\\\\\ \pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides} \\\\\\ cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s](https://tex.z-dn.net/?f=%5Cbf%20sec%28s%29%3Dcos%28s%29%5Cqquad%20but%5Cimplies%20sec%28%5Ctheta%29%3D%5Ccfrac%7B1%7D%7Bcos%28%5Ctheta%29%7D%0A%5C%5C%5C%5C%5C%5C%0Athus%5Ccfrac%7B1%7D%7Bcos%28s%29%7D%3Dcos%28s%29%5Cimplies%201%3Dcos%5E2%28s%29%5Cimplies%20%5Cpm%20%5Csqrt%7B1%7D%3Dcos%28s%29%0A%5C%5C%5C%5C%5C%5C%0A%5Cpm%201%3Dcos%28s%29%5Cimpliedby%20%5Ctextit%7Bnow%20taking%20%7Dcos%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Acos%5E%7B-1%7D%28%5Cpm%201%29%3Dcos%5E%7B-1%7D%5Bcos%28s%29%5D%5Cimplies%20cos%5E%7B-1%7D%28%5Cpm%201%29%3D%5Cmeasuredangle%20s)
namely if sec(s) = cos(s)
then solving for "s"
thus