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levacccp [35]
3 years ago
11

How do you convert ounces to grams

Chemistry
2 answers:
enyata [817]3 years ago
8 0
1 ounce =28.34952g the mass M oz×28.34952.example convert 5 oz to grams.m g=5oz×28.34952=141.7476 g.hope that helped a little
jok3333 [9.3K]3 years ago
4 0
However many ounces you have, just multiply that by 28.34952. The answer to that is the conversion. so 5 ounces is 141.7476. Proof below.

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A chemical engineer has determined by measurements that there are 69.0 moles of hydrogen in a sample of methyl tert-butyl ether.
Juli2301 [7.4K]
<span>5.75 moles The formula for methyl tert-butyl ether is (CH3)3COCH3, so a single molecule has 5 carbon, 12 hydrogen, and 1 oxygen atoms. So for every 12 moles of hydrogen, there's 1 mole of oxygen. So simply divide the number of moles of hydrogen by 12 to get the number of moles of oxygen. 69.0 / 12 = 5.75 Therefore there's 5.75 moles of oxygen in the sample.</span>
3 0
3 years ago
If all of the energy from burning 281.0 g of propane (ΔHcomb,C3H8 = –2220 kJ/mol) is used to heat water, how many liters of wate
lapo4ka [179]

This problem is providing us with the mass of propane, its enthalpy of combustion, and the initial and final temperature of water that can be heated from the burning of this fuel. At the end, the result turns out to be 42.27 L.

<h3>Combustion:</h3>

In chemistry, combustion reactions are based on the burning of fuels by using oxygen and producing both carbon dioxide and water. For propane, we will have:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

Hence, we can calculate the heat released from this reaction by using the mass, which has to be converted to moles, and the given enthalpy of combustion:

Q=281.0g*\frac{1mol}{44.09g}*-2220\frac{kJ}{mol}*\frac{1000J}{1kJ}\\ \\ Q=-1.415x10^7 J

<h3>Calorimetry:</h3>

In chemistry, we can analyze the mass-specific heat-temperature-heat relationship via the most general heat equation:

Q=mC\Delta T

Thus, since Q was obtained from the previous problem, but the sign change because the released heat is now absorbed by the water, one can calculate the mass of water that rises from 20.0°C to 100.0°C with this heat:

m=\frac{Q}{C\Delta T} =\frac{1.415x10^7J}{4.184\frac{J}{g\°C}(100.0\°C-20.0\°C)}\\ \\m=4.227x10^4g

Finally, we convert it to liters as required:

V=4.227 x10^4g*\frac{1mL}{1.00g}*\frac{1L}{1000mL}  \\\\V=42.27L

Learn more about calorimetry: brainly.com/question/1407669

4 0
2 years ago
Sweat is made up of all EXCEPT what?<br> *<br> A.Sugar<br> B.Salt<br> C.Urea<br> D.Urine
andreev551 [17]
D, Urine.

Just google what sweat is made of and it gives you all of the answers except for urine. Also you’d probably smell really bad if your sweat had urine in it. Hope this helps! :)
8 0
3 years ago
Benzoic acid is a weak monoprotic acid. It has a pKa of 4.20. A student transferred 25.00mL of 0.126M benzoic acid into a beaker
Andru [333]

Answer:

pH of the benzoic acid solution = 3.35

Explanation:

Benzoic acid is a weak monoprotic acid

  pKa = 4.2

⇒ Ka = 6.3 x 10⁻⁵

                                  C₆H₅COOH ⇄ C₆H₅COO⁻ + H⁺

Initial concentration      C molar             0                0

At equilibrium               (c - cα)               cα               cα

                      Acid dissociation constant Ka = \frac{c\alpha X c\alpha  }{c - c\alpha }

                                              ⇒          6.3 x 10⁻⁵ = α²c ................(1)

(for weak electrolyte 1 -α = 1)

Concentration of benzoic acid C = 25 x 0.126 x 10⁻³ = 0.00315 molar

                  From eqn (1)

                          α² = \frac{6.3 X 10^{-5} }{0.00315}

                    ⇒  α = √(\frac{6.3 X 10^{-5} }{0.00315} )

                    ⇒  α = 0.14

So concentration of H⁺ ion = 0.14 x 0.00315 = 0.000441

pH = - log 0.000441 = 3.35    

We not considered H⁺ concentration of water because pH  < 7                  

5 0
4 years ago
Given 1 cm3 = 1 mL What is the volume in cubic centimeters of a 500 ml beaker? cm3​
makvit [3.9K]

Answer:

500 cubic centimeters of water

3 0
3 years ago
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