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malfutka [58]
2 years ago
5

2) A balloon was inflated to a volume of 5.0 liters at a temperature of

Chemistry
1 answer:
TEA [102]2 years ago
8 0

Answer:

6.12 L

Explanation:

Given that,

Initial volume, V₁ = 5 L

Initial temperature, T₁ = 7.0°C = 343 K

Final temperature, T₂ = 147°C = 420 K

We need to find its new volume. The relation between volume and temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{5\times 420}{343}\\\\V_2=6.12\ L

So, the new volume is 6.12 L.

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