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V125BC [204]
2 years ago
12

2 Na + 1 Cl2 → 2 Naci How many grams of NaCl are created from 23,2 grams Cl2?

Chemistry
1 answer:
evablogger [386]2 years ago
3 0

37 grams of NaCl (when I mean equivalent I mean the ratio of the equation is 1:2 for moles or Cl2 and NaCl

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borishaifa [10]
Sodium, Atomic mass: 22.989769 g
You can see in a periodic table
5 0
3 years ago
It's 32°F (0°C) outside under normal atmospheric conditions (1 atm) at a stunt
Korolek [52]

The volume of the balloon is approximately 2652 liters.

<h3>How to determine the volume occupied by the gas in a balloon </h3>

Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass (M), in kilograms per kilomole, and mass of the gas (m), in kilograms. The volume occupied by the gas (V), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:

V = \frac{m\cdot R_{u}\cdot T}{P\cdot M}   (1)

Where:

  • R_{u} - Ideal gas constant, in kilopascal-cubic meters per kilomole-Kelvin.
  • T - Temperature, in Kelvin
  • P - Pressure, in kilopascals

If we know that m = 0.239\,kg, R_{u} = 8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K}, T = 273.15\,K, P = 101.325\,kPa and M = 2.02\,\frac{kg}{kmol}, then the volume of the balloon is:

V = \frac{(0.239\,kg)\cdot \left(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)\cdot (273.15\,K)}{\left(101.325\,kPa\right)\cdot \left(2.02\,\frac{kg}{kmol} \right)}

V = 2.652\,m^{3} (2652\,L)

The volume of the balloon is approximately 2652 liters. \blacksquare

To learn more on ideal gases, we kindly invite to check this verified question: brainly.com/question/8711877

4 0
2 years ago
How many moles of zinc, Zn, are in 1.31×1024 Zn atoms?
liubo4ka [24]

Answer:

=7.89013× 10^47 moles of zinc

Explanation:

1 atom contains 6.023×10^23 moles.

1.31×10^24 atoms of zinc contain6.023×10^24×1.31×10^.24

6 0
2 years ago
Solve the following equation (y = 1.2345x – 0.6789) for x, given that y = 0.570
Andrews [41]

x = 1.01

Explanation:

Given equation:

   y = 1.2345x – 0.6789

   y = 0.570

Problem:

Solving for x

The variables in this equation are y and x

They can take up any value since they are variables.

  Since we have been given y = 0.570

        y = 1.2345x – 0.6789

To solve for x, we simply substitute for y in the equation;

     since  y = 0.570

     0.57 = 1.2345x – 0.6789

    add 0.6789 to both sides;

 0.57 + 0.6789 =  1.2345x – 0.6789 + 0.6789

  1.2489‬ =   1.2345x

Divide both sides by  1.2345

 \frac{1.2489}{  1.2345} = \frac{  1.2345x }{ 1.2345}

    x = 1.01

learn more:

Equations brainly.com/question/9045597

#learnwithBrainly

 

7 0
3 years ago
Based upon the information provided in the class, which of the following bond types is the strongest? Question options:
Zigmanuir [339]

Answer: A hydrogen bonding is interaction between lone pair and hydrogen atom. An Ion-Dipole interaction is the interaction between an ion formed and a dipole. Dipole forms because of the electronegativity difference between two atom participating in the bond formation, and an ion is formed when an atom gains or lose electron. This ion-dipole interaction is strongest interaction.

Therefore, The right choice is (B)

7 0
3 years ago
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