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V125BC [204]
2 years ago
12

2 Na + 1 Cl2 → 2 Naci How many grams of NaCl are created from 23,2 grams Cl2?

Chemistry
1 answer:
evablogger [386]2 years ago
3 0

37 grams of NaCl (when I mean equivalent I mean the ratio of the equation is 1:2 for moles or Cl2 and NaCl

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Iron (Fe) is a/n:<br> Element<br> Mixture<br> Compound<br> Solution
Karo-lina-s [1.5K]

Answer:

Element

Explanation:

Iron is an element

4 0
2 years ago
How many molecules of ascorbic acid(vitaminC,<br> C6H8 O6 )are in a 500 mg<br> tablet?
Olegator [25]

Answer:

1.71 × 10²¹ molecules

Explanation:

1 gram is equal to 1000 milligrams. The mass in grams corresponding to 500 mg is:

500 mg × (1 g / 1000 mg) = 0.500 g

The molar mass of ascorbic acid is 176.12 g/mol. The moles corresponding to 0.500 grams of ascorbic acid are:

0.500 g × (1 mol/ 176.12 g) = 0.00284 mol

In 1 mole of ascorbic acid, there are 6.02 × 10²³ molecules of ascorbic acid (Avogadro's number). The molecules in 0.00284 moles are:

0.00284 mol × (6.02 × 10²³ molecules/ 1 mol) = 1.71 × 10²¹ molecule

7 0
3 years ago
Read 2 more answers
How many grams of hydrogen gas will form in this equation?
FrozenT [24]
The Law of Conservation of Mass states that matter cannot be created nor destroyed. The first two reactants have a total of 23 grams so therefore the product must have 23 grams as well.
23 - 16 = 7
There would be 7 grams of hydrogen gas.
7 0
2 years ago
5.80 gg of NaCl in 350. mL of a NaClsolution
Delicious77 [7]

Answer:

Solution is 0.28 M

You can also say, [NaCl] = 0.28 mol/L

Explanation:

As you have a solute mass and the solution's volume, you may find the molarity concentration of solution.

Molarity specifies the moles of solute in 1 L of solution

We convert the volume of solution to L → 350 mL . 1L / 1000 mL = 0.350L

We convert the mass of solute to moles → 5.80 g . 1mol / 58.45 g = 0.0992 moles

Molarity (mol/L) = 0.0992 mol /0.350L = 0.28M

6 0
2 years ago
Which of these factors will cause a solid solute to dissolve faster?
Nostrana [21]
I believe the answer you are looking for is the 4th one.
8 0
3 years ago
Read 2 more answers
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