, or 8.60
Just use the distance formula
x = the length of one piece
y = the length of the other piece
the total length is 100 cm this means
x + y = 100
one piece is 16 inches longer than the other
first we need to convert inches to cm:
1 in = 2.54 cm
16 in = 2.54*16 = 40.64
now we can write
x = y + 40.64
by solving the system of equations
x + y = 100
x = y + 40.64
we find
x = 70.32 cm
y = 29.68 cm
the lengths of the two pieces are 70.32 cm and 29.68 cm.
The distance between two points knowing theirs coordinates:
AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(-2,4) & B(0,-6) Given
A(x₁,y₁) & B(y₂,y₁)
AB =√[(0-(-2))²+(-6-4)²] =√(104) = 10.198 ≈ 10.2
Answer:
Is this for a Trig class? just wondering
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
we want to find the Hypotenuse (Hyp) and are given an angle and the adjacent side (adj) sooo use CAH , b/c it has all of the pieces
Cos(37) = Adj / Hyp
Cos(37) = 11 / Hyp
swap Cos(37) and Hyp... an algebra trick you should know from college algebra or where ever you learned algebra
Hyp = 11 / Cos(37)
now solve with your handy TI 83 / 84 / 89 calculator :) if you don't have one go get one . :D get the 89 if you are going into engineering classes... the 83 /84 if not. (obviously there are many many other good choices, i'm not really a calculator salesman on the side :D )
Hyp = 13.77349...
Hyp = 13.8 ( rounded to nearest 10th ) :)
