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Tresset [83]
2 years ago
10

Plz help ASAP! 10 points

Mathematics
1 answer:
loris [4]2 years ago
4 0
There’s this app called Socratic that you can use. It’s like this one but it’s a little different
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A recipe for a loaf of bread calls for 2/3 of a cup of flour. If Milo used 12 cups of flour, how many loafs of bread did he prep
Aloiza [94]
The answer is:

1/2 cups of flour can make 1 loaf.

1 cup would make =   1 /(1/2) = 2 loaves.

12 cups of flour would then make =  12*2 = 24

= 24 loaves.

[Please Mark as Brainliest]

7 0
3 years ago
Read 2 more answers
an online seed supplier packages a seed mix that costs the company 20.70$ per pound the mix includes poppy seeds costing 24$ per
seraphim [82]

Answer:

The quantity of clover seeds in pounds to be added is 11.14

Step-by-step explanation:

Let

x -----> the quantity of poppy seeds in pounds

y -----> the quantity of clover seeds in pounds

we know that

24(x)+13(y)=20.70(x+y) -----> equation A

x=26\ pounds ----> equation B

substitute equation B in equation A and solve for y

24(26)+13(y)=20.70(26+y)

624+13y=538.2+20,70y

20.70y-13y=624-538.2

7.7y=85.8

y=11.14\ pounds

therefore

The quantity of clover seeds in pounds to be added is 11.14

8 0
3 years ago
Read 2 more answers
What number complete the square x^2 +\- bx
kati45 [8]
Take 1/2 of b and squaer it so (b/2)^2 would complete the square (sign doesn't matter becaus when squareing, sign goes positive)
7 0
3 years ago
Todd swam his race in 26.785 seconds while Frank swam his race in 29.07 seconds. What was the difference in their times?
Alexus [3.1K]
All you got to do is subtract. 2.285
5 0
3 years ago
Read 2 more answers
A stadium has 45,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. If section C held 300 fewer
White raven [17]

Answer:

Let's define the variables:

A = number of seats in section A.

B = number of seats in section B.

C = number of seats in section C.

We have the equations:

A + B + C = 45,000.

C - 300 = B/2

A*$28 + B*$24 + C*$20 = $1,139,200

This is a system of equations, the first step to solve this is to isolate one variable in one of the equations, and then replace it in the others.

I will isolate C in the second equation:

C = B/2 + 300.

Now let's replace this in the other two equations:

A + B + B/2 + 300 = 45,000

A*$28 + B*$24 + (B/2 + 300)*$20 = $1,139,200

Let's simplify these equations:

A + B*(3/2) = 44,700

A*$28 + B*$34 + $6,000 = $1,139,200

Now let's isolate A in the first equation:

A = 44,700 - B*(3/2)

Let's replace this in the other equation:

(44,700 - B*(3/2))*$28 + B*$34 + $6,000 = $1,139,200

Now let's solve this for B.

-B*$8 + $1,252,200 = $1,139,200

-B*$8 =  $1,139,200 - $1,252,200  = -$113,000

B = $113,000/8 = 14,125

Now we can replace that in the equations:

A =  44,700 - B*(3/2) =  44,700 - 14,125*(3/2) = 23,512.5, that we should round up to 23,513.

And C = B/2 + 300 = 7362.5

As we rounded the previous one up, we should round this one down to 7362.

3 0
2 years ago
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