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Illusion [34]
3 years ago
12

Indicate how the concentration of each species in the chemical equation will change to reestablish equilibrium after changing th

e concentration of the reactant or product. An up arrow indicates an increase in concentration, a down arrow indicates a decrease in concentration, and leaving it blank means there is no change in the concentration
C2H4(g)+Cl2------------>2C2H4Cl2(g)
<-----------
after the concentration of C2H4 is increased __________.
after the concentration of C2H4C12 is increased _________.
Chemistry
1 answer:
Viktor [21]3 years ago
7 0

Explanation:

Since this is an equilibrium problem, we apply le chatelier principle. This principle states that whenever a system at equilibrium is disturbed due to change in several factors, it would move in a way to annul such change.

C2H4(g) + Cl2 ⇔ 2C2H4Cl2(g)

When the concentration of C2H4 is increased, there is more reactant sin the system. In order to annul this change, the equilibrium position will shift to the right favoring product formation.

When the concentration of C2H4Cl2 is increased, there is more product in the system. To annul this change, the equilibrium position will shift to the left, favoring reactant formation.

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ludmilkaskok [199]

answer : D= m/v

Explanation:

all about density and mass and size of the molecules in a liquid and how close they are packed together

5 0
3 years ago
Given that 10.00mL of 0.1894M CH3COOH was titrated with 0.2006M NaOH in this experiment, calculate the volume, in mL, of NaOH re
sertanlavr [38]

Answer:

V_{base}=9.442mL

Explanation:

Hello!

In this case, when acetic acid is titrated with sodium hydroxide, the following chemical reaction is carried out:

CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O

Whereas there is a 1:1 mole ratio between the acid and the base, which means that at the equivalence point we evidence:

n_{acid}=n_{base}

Which in terms of volumes and concentrations is written as:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, solving for the required volume of base, we obtain:

V_{base}=\frac{M_{acid}V_{acid}}{M_{base}}=\frac{0.1894M*10.00mL}{0.2006M}\\\\ V_{base}=9.442mL

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7 0
3 years ago
Into which chambers does blood enter the heart and through which chambers does blood leave the heart?
slava [35]

Answer:

Blood enters the right atrium and passes through the right ventricle.

Explanation:

The two bottom chambers are the right ventricle and the left ventricle. These pump blood out of the heart.

4 0
3 years ago
Read 2 more answers
What alteration to an HCN channel will reduce the transport of K+ in favor of Na+ transport? HCN channels are permeable to both
kipiarov [429]

Answer:

Decreasing the diameter of the channel by removing aa's. Since Na+ is chemically similar to K+, one can assume the difference must be due to the size of the atom. The K+ ion is larger than the Na+ ion, so reducing the diameter of the channel can allow Na+ to enter while preventing K+ entry. This explains clearly and perfectly how reducing the diameter reduces the

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6 0
3 years ago
How many moles and molecules are there in 250g of hydrogen nitrate, HNO3
Viefleur [7K]

Answer:

Number of molecules = 23.9  × 10²³ molecules

Number of moles = 3.97 mol

Explanation:

Mass of HNO₃ = 250 g

Number of moles = ?

Number of molecules = ?

Solution:

Number of moles = mass / molar mass

Number of moles = 250 g/63 g/mol

Number of moles = 3.97 mol

Number of molecules:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 250 g of HNO₃:

250 g/ 63 g/mol = 3.97 mole

3.97 × 6.022 × 10²³ molecules = 23.9  × 10²³ molecules

6 0
3 years ago
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