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Anarel [89]
3 years ago
7

Express the product of 9.0 x 10^-4m and 8.1 x 10^4m using the correct number of significant digits

Chemistry
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

7.3 × 10¹ m²

Explanation:

The language "product" means that we must multiply the numbers given to get our answer.

9.0 × 10⁻⁴ m × 8.1 × 10⁴ m = 7.3 × 10¹ m²

The significant figures rule for multiplication is that we must us the amount of significant figures in the number with the least significant figures, in this question this is 2 significant digits from both 9.0 × 10⁻⁴ m and 8.1 × 10⁴ m.

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Chlorine (Cl) is 76% chlorine-35 and 24% chlorine-37. Determine the average atomic mass of chlorine. Show/Explain work.
Flura [38]

Answer:

Average atomic mass of chlorine is 35.48 amu.

Explanation:

Given data:

Percent abundance of Cl-35 = 76%

Percent abundance of Cl-37 = 24%

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (76×35)+(24×37) /100

Average atomic mass =  2660 + 888 / 100

Average atomic mass  = 3548/ 100

Average atomic mass = 35.48 amu

Average atomic mass of chlorine is 35.48 amu.

4 0
3 years ago
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Trace amounts of sulfur (S) in coal are burned in the presence of diatomic oxygen (O2) to form sulfur dioxide (SO2). Determine t
Mashcka [7]

Answer:

0.99 kg O₂

1.9 kg SO₂

Explanation:

Let's consider the reaction between sulfur and oxygen to form sulfur dioxide.

S + O₂ → SO₂

The mass ratio of S to O₂ is 32.07:32.00. The mass of oxygen required to react with 1 kg of sulfur is:

1 kg S × (32.00 kg O₂/32.07 kg S) = 0.998 kg O₂

The mass ratio of S to SO₂ is 32.07:64.07. The mass of sulfur dioxide formed when 1 kg of sulfur is burned is:

1 kg S × (64.07 kg SO₂/32.07 kg S) = 1.99 kg SO₂

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Poly(lactic acid) (PLA) has received much recent attention because the lactic acid monomer [CH3CH(OH)COOH] from which it is made
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Answer:

The structure is shown in the figure.

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There is condensation polymersiation in case of lactic acid with the removal of water molecule (dehydration) leading to formation of poly lactic acid.

The structure of PLA is shown in the figure.

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