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Anarel [89]
3 years ago
7

Express the product of 9.0 x 10^-4m and 8.1 x 10^4m using the correct number of significant digits

Chemistry
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

7.3 × 10¹ m²

Explanation:

The language "product" means that we must multiply the numbers given to get our answer.

9.0 × 10⁻⁴ m × 8.1 × 10⁴ m = 7.3 × 10¹ m²

The significant figures rule for multiplication is that we must us the amount of significant figures in the number with the least significant figures, in this question this is 2 significant digits from both 9.0 × 10⁻⁴ m and 8.1 × 10⁴ m.

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Which type of reaction happens when a base is mixed with an acid? question 1 options:?
madreJ [45]
Chemicals cancel each other out and produce a salt and water. A neutralization reaction my also occur
7 0
3 years ago
I need help with this problem !
Sloan [31]

Answer:

3

Explanation:

7 0
3 years ago
An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit
Anon25 [30]

<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol

<u>Explanation:</u>

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of triprotic acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL

Putting values in above equation, we get:

3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

7 0
3 years ago
can you tell what the genotype of the purple flowered parent is from the information in the punnets square? explain why or why n
Nina [5.8K]

We will not be able to tell the genotype of the purple parent as it can either be a homo_zygous dominant or hetero_zygous. Without the complete genotype of the offspring, we would not be able to tell.

6 0
2 years ago
The reaction of equal molar amounts of benzene, C6H6, and chlorine, Cl2, carried out under special conditions, yields a gas and
WINSTONCH [101]

Answer : The molecular formula of a compound is, C_6H_5Cl_1

Solution : Given,

Mass of C = 64.03 g

Mass of H = 4.48 g

Mass of Cl = 31.49 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of Cl = 35.5 g/mole

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{64.03g}{12g/mole}=5.34moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{4.48g}{1g/mole}=4.48moles

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{31.49g}{35.5g/mole}=0.887moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{5.34}{0.887}=6.02\approx 6

For H = \frac{4.48}{0.887}=5.05\approx 5

For Cl = \frac{0.887}{0.887}=1

The ratio of C : H : Cl = 6 : 5 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = C_6H_5Cl_1

The empirical formula weight = 6(12) + 5(1) + 1(35.5) = 112.5 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{112.5}{112.5}=1

Molecular formula = (C_6H_5Cl_1)_n=(C_6H_5Cl_1)_1=C_6H_5Cl_1

Therefore, the molecular of the compound is, C_6H_5Cl_1

5 0
3 years ago
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