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Masja [62]
3 years ago
11

Ima Chemist found the density of Freon-11 (CFCl3) to be 5.58 g/L under her experimental conditions. Her measurements showed that

the density of an unknown gas was 4.38 g/L under the same conditions. What is the molar mass of the unknown?
Chemistry
1 answer:
PIT_PIT [208]3 years ago
3 0

If we assume this two gases behave like ideal gas, then we use the ideal gas law PV=nRT, where P is the pressure, V is the volume, n number of moles, R gas constant and T the temperature in kelvins. As well as the density formula D=\frac{m}{V}. First we calculate the molarity for Freon

CFCl_3 = (12+ 18.998 + 3 \times 35.453) =137.36\ g/mol.

The number of moles for freon are

D=\frac{m}{V} =\frac{ nM}{L} \implies n= \frac{DL}{M} = \frac{5.58 g \times L}{L \times 137.36g/mol}= 0.0406 mol

We know n=\frac{m}{M}, so we insert this concept to our ideal gas equation

PV=n \times RT=\frac{m}{M} \times RT= \frac{mRT}{M}. Since D=\frac{m}{V}, we insert this concept to the formula

PV=\frac{mRT}{M} \\P=\frac{mRT}{VM} = \frac{DRT}{M} \\\\\implies M= \frac{DRT}{P}. The measurements take place in same conditions so,

M=\frac{DRT}{P} = \frac{4.38g}{L}\times \frac{1L}{0.0406mol} = 107.9\ g/mol

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1. If you have 8.1 g CO₂ and 2.3 g H₂, which one is the limiting reactant. Show your work. 2. Calculate the theoretical yield of
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Answer:

2.95 g of CH₄

Explanation:

To start this, we determine the equation:

4H₂  + CO₂ →  CH₄  +  2H₂O

4 moles of hydrogen react to 1 mol of carbon dioxide in order to produce 1 mol of methane and 2 moles of water.

To determine the limiting reactant, we need to know the moles of each reactant.

8.1 g . 1 mol/ 44g = 0.184 moles of carbon dioxide

2.3 g . 1mol / 2g = 1.15 moles of hydrogen

4 moles of hydrogen react to 1 mol of CO₂

Then, 1.15 moles may react to (1.15 . 1) /4 = 0.2875 moles

We only have 0.184 moles of CO₂, so this is the limiting reactant. Not enough CO₂ to complete the 0.2875 moles that are needed.

Ratio is 1:1. 1 mol of CO₂ produces 1 mol of methane

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3 years ago
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One chemical reaction is called the Haber process, a method for preparing ammonia by reacting nitrogen gas with hydrogen gas:


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You know the reactants and the product for this reaction, and you can’t change them. You can’t change the compounds, and you can’t change the subscripts, because that would change the compounds.


So the only thing you can do to balance the equation is add coefficients, whole numbers in front of the compounds or elements in the equation. Coefficients tell you how many atoms or molecules you have.


For example, if you write the following, it means you have two water molecules:


Each water molecule is composed of two hydrogen atoms and one oxygen atom. So with two water molecules (represented above), you have a total of 4 hydrogen atoms and 2 oxygen atoms.


You can balance equations by using a method called balancing by inspection. You take each atom in turn and balance it by adding appropriate coefficients to one side or the other.


With that in mind, take another look at the equation for preparing ammonia: HOPE THIS HELPS



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