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4 years ago

10

Earthquakes are usually caused by tectonic plates slipping past each other. An earthquake generates seismic waves of energy that

travel through the ground. What would you expect to happen when a seismic wave passes from the ground into a body of water?

1 answer:

lyudmila [28]4 years ago

6 0

Answer:

I think a tsunami

Explanation:

im not 100% sure but that would make the most sense to me hope this helped!

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Please help, what's the efficiency of the two pulleys

lutik1710 [3]

Answer:20cm

Explanation:

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3 years ago

Check and double-click on the red polygon for the Henry Mountains laccolith complex in the folder labeled Problem 1. This comple

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3 years ago

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The angle between incident ray and reflected ray is 130.what is the value of angle of incidence

Artyom0805 [142]

Answer:

65

Explanation:

as i = r , so i + i = 130

so , i = 130/2 =65

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3 years ago

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The combination of an applied force and a friction force produces a constant total torque of 35.5 N · m on a wheel rotating abou

Cerrena [4.2K]

Answer:

a) $I = 19.799\,kg\cdot m^{2}$ , b) $T = -3.405\,N\cdot m$ , c) $n_{T} \approx 54.842\,rev$

Explanation:

a) The net torque is:

$T = I\cdot \alpha$

Let assume a constant angular acceleration, which is:

$\alpha = \frac{\omega-\omega_{o}}{t}$

$\alpha = \frac{10.4\,\frac{rad}{s} - 0\,\frac{rad}{s} }{5.80\,s}$

$\alpha = 1.793\,\frac{rad}{s^{2}}$

The moment of inertia of the wheel is:

$I = \frac{T}{\alpha}$

$I = \frac{35.5\,N\cdot m}{1.793\,\frac{rad}{s^{2}} }$

$I = 19.799\,kg\cdot m^{2}$

b) The deceleration of the wheel is due to the friction force. The deceleration is:

$\alpha = \frac{\omega-\omega_{o}}{t}$

$\alpha = \frac{0\,\frac{rad}{s} - 10.4\,\frac{rad}{s}}{60.4\,s}$

$\alpha = - 0.172\,\frac{rad}{s^{2}}$

The magnitude of the torque due to friction:

$T = (19.799\,kg\cdot m^{2})\cdot (-0.172\,\frac{rad}{s^{2}} )$

$T = -3.405\,N\cdot m$

c) The total angular displacement is:

$\theta_{T} = \theta_{1} + \theta_{2}$

$\theta_{T} = \frac{(10.4\,\frac{rad}{s} )^{2}-(0\,\frac{rad}{s} )^{2}}{2\cdot (1.793\,\frac{rad}{s^{2}} )} + \frac{(0\,\frac{rad}{s} )^{2}-(10.4\,\frac{rad}{s} )^{2}}{2\cdot (-0.172\,\frac{rad}{s^{2}} )}$

$\theta_{T} = 344.580\,rad$

The total number of revolutions of the wheel is:

$n_{T} = \frac{\theta_{T}}{2\pi}$

$n_{T} = \frac{344.580\,rad}{2\pi}$

$n_{T} \approx 54.842\,rev$

5 0

4 years ago

Find mass when kinetic energy is 1.6 J and velocity is 0.2 m/s

klio [65]

Answer:

4kg

Explanation:

Given parameters:

Kinetic energy = 1.6J

Velocity = 0.2m/s

Unknown:

Mass of the body = ?

Solution:

The kinetic energy of a body is the energy due to the motion of the body.

It is mathematically expressed as;

Kinetic energy = $\frac{1}{2}$ m v²

m is the mass

v is the velocity

1.6 = $\frac{1}{2}$ x 0.2 x v²

1.6 = 0.1v²

v² = 16

v = 4kg

5 0

3 years ago