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3 years ago

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Does heavy force work under conditions of weightlessness in such an artificial earth satellite?

1 answer:

Afina-wow [57]3 years ago

3 0

Answer: That is to say, a satellite is an object upon which the only force is gravity. Once launched into orbit, the only force governing the motion of a satellite is the force of gravity. Newton was the first to theorize that a projectile launched with sufficient speed would actually orbit the earth.

Explanation: Because Earth-orbiting objects follow elliptical paths around Earth and not a straight line, forces cannot, by definition, be balanced. Force is directional. It is a push or a pull in a particular direction.

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An organism that breaks down dead and decaying organisms to obtain energy

s2008m [1.1K]

That would be a decomposer

Hope this helps!

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3 years ago

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Star Characteristic Questions<br> What are the two things that stars are emitting into space?

katovenus [111]

Answer:

1- Light , 2-Heat , ( and Nuclear energy)

Explanation:

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3 years ago

Anders suffered a shock when his electric radio dropped into the bathtub--while anders was taking a bath. Anders argued that he

blsea [12.9K]

The claim Anders is most likely to make is the failure of the manufacturer to warn about such risk.

<h3>What is a Risk?</h3>

This is defined as the possibility of something bad happening and in this case it is electric shock when dropped into the bathtub.

Anders can decide to sue for not warning against risk of electric shock when in contact with water.

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2 years ago

The battery is made up of three 1.5 V cells.

IrinaVladis [17]

Answer: 4.5 V

Explanation:

Given

The voltage of each cell is 1.5 V

If they are connected end to end their potential added to give a higher potential i.e. 1.5+1.5+1.5=4.5 V

6 0

3 years ago

A child is riding a merry-go-round that has an instantaneous angular speed of 1.25 rad/s and an angular acceleration of 0.745 ra

skelet666 [1.2K]

Answer:

So the acceleration of the child will be $8.05m/sec^2$

Explanation:

We have given angular speed of the child $\omega =1.25rad/sec$

Radius r = 4.65 m

Angular acceleration $\alpha =0.745rad/sec^2$

We know that linear velocity is given by $v=\omega r=1.25\times 4.65=5.815m/sec$

We know that radial acceleration is given by $a=\frac{v^2}{r}=\frac{5.815^2}{4.65}=7.2718m/sec^2$

Tangential acceleration is given by

$a_t=\alpha r=0.745\times 4.65=3.464m/sec^$

So total acceleration will be $a=\sqrt{7.2718^2+3.464^2}=8.05m/sec^2$

7 0

3 years ago