Answer:
vb = 22.13 m/s
Explanation:
ma = 124 kg
mb = 13 kg
vi = 2.10 m/s
According to the property of conservation of momentum, and considering that, initially, both the astronaut and the bag moved together at 2.10 m/s:

The minimum final velocity of the bag, vb, the will keep the astronaut from drifting away forever occurs when va = 0:

The minimum final velocity of the bag is 22.13 m/s.
The farther apart the two objects, the weaker the gravitational attraction between them.
We are given the following:
thickness, T = 0.155 mm
charge-carrier density, n = 1.05 x 10^25 / m3
current, I = 2.67 A
voltage, V = 4.89 mV
We are asked to get the magnetic strength, B
To solve this, we use the Hall Effect formula:
V = - IB / neT
where e is the charge of an electron which is e = 1.60 x 10^-19 and B is the magnetic field
Rearranging the formula
B = -V n e T / I
Substituting the given values
B = - (4.89 x 10^-3 V) (1.05 x 10^25 / m3) (0.155 x 10^-3 m) / 2.67 A
B = -2.98 x 10^18 Teslas