To contrast inner and outer planets we will start with the climate of the planets and then move on to there lighting. To start the planets closet to the sun, mercury, venus, earth and mars, are all hot compared to the further one, jupiter, saturn, uranus, neptune. This distance also makes the farthe away planets darker than the ones closer. Now to compare all the planets vary from either gass or solid, rocky or icy. All of them spin around the sun and all have objects spinning around them, moons.
 
        
             
        
        
        
Answer:
0.911 atm
Explanation:
In this problem, there is no change in volume of the gas, since the container is sealed.
Therefore, we can apply Gay-Lussac's law, which states that:
"For a fixed mass of an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"
Mathematically:

where
p is the gas pressure
T is the absolute temperature
For a gas undergoing a transformation, the law can be rewritten as:

where in this problem:
 is the initial pressure of the gas
 is the initial pressure of the gas
 is the initial absolute temperature of the gas
 is the initial absolute temperature of the gas
 is the final temperature of the gas
 is the final temperature of the gas
Solving for p2, we find the final pressure of the gas:

 
        
             
        
        
        
Answer:
power emitted is 1.75 W
Explanation:
given data 
length l = 5 cm = 5 × m
 m
diameter d = 0.074 cm = 74 × m
 m
total filament emissivity = 0.300
temperature = 3068 K
to find out 
power emitted
solution
we find first area that is π×d×L
area = π×d×L
area = π×74 × ×5 ×
×5 × 
 
area = 1162.3892  × m²
 m²
so here power emitted  is express as 
power emitted  = E × σ × area × (temperature)^4
put here all value
power emitted  = 0.300× 5.67 × 1162.3892  × × (3068)^4
  × (3068)^4
power emitted = 1.75 W