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2 years ago

Velocity can best be described by which of the following statements?

Physics

2 answers:

pogonyaev2 years ago

8 0

Answer: Velocity can best be described as, the speed in a given direction.

Explanation: To find the answer, we need to know more about the Velocity of a body.

<h3>What is Velocity of a body?</h3>

Velocity is the rate of change of displacement.
It's a vector quantity and is measured in m/s.
It can be positive, negative or zero.
A body is said to be in uniform motion, then its velocity remains constant.
Change in velocity can be a change in speed.
The magnitude of velocity is less than or equal to speed.

Thus, we can conclude that, the option C is best describing velocity.

Learn more about velocity here:

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zalisa [80]2 years ago

3 0

The speed in a certain direction is the best way to define velocity.

We need to learn more about a body's velocity in order to locate the solution.

<h3>What does a body's velocity mean?</h3>

The rate of change of displacement is known as velocity.

It has a vector value and is expressed in m/s.

It may be zero, negative, or positive.

When a body is moving uniformly, its velocity is said to be constant.

Speed might alter depending on the change in velocity.

Speed and the magnitude of velocity are not comparable.

As a result, we can say that choice C best captures velocity.

Learn more about the velocity here:

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USPshnik [31]

Answer:

The time is $t = 2.595 \ s$

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Explanation:

From the question we are told that

The height of the cliff is $h = 33 \ m$

Generally from kinematic equation we have that

$h = ut + \frac{1}{2} gt^2$

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$33 = 0 * t + \frac{1}{2} 9.8 * t^2$

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3 years ago

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2 years ago

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3 years ago

A long solenoid with 8.22 turns/cm and a radius of 7.00 cm carries a current of 19.4 mA. A current of 3.59 A exists in a straigh

daser333 [38]

Answer:

a. 3.039cm

b.magnetic field is $B=2.958\times10^{-5}T$

Explanation:

Direction of the solenoid magnetic field is along the axis of the solenoid. and magnetic field due to the wire perpendicular to that due to the solenoid.. Magnetic field at r is given by:

$\overrightarrow B = \overrightarrow B_s+ \overrightarrow B_w,\ \ \ \ \ \overrightarrow B_s\perp \overrightarrow B_w$

Angle of net magnetic field from axial direction is given by:

$tan\ \theta=\frac{B_w}{B_s}$ ,

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$B_s=\mu_onI_s, \ \ \ \ n=(8.22 t/cm)(100cm/m)=822turn/m$

Field due to wire:

$B_w=\frac{\mu_oI_w}{2\pi r}$

Therefore, r:

$tan\ \theta=\frac{B_w}{B_s}\\\\=\frac{\mu_oI_w}{2\pi r(\mu_o nI_s)}\\\\r=\frac{I_w}{2\pi nI_stan \ \theta}\\\\r=\frac{3.59A}{2\pi\times822\times19.4\times10^{-3}A \ tan 49.7\textdegree}\\\\r=3.039cm$

Hence, the radial distance is 3.039cm

b.The magnetic field strength is given by:

$B=\sqrt{B_w^2+B_s^2}\\\\tan 49.7\textdegree=\frac{B_w}{B_s}\\\\1.179=\frac{B_w}{B_s}\\\\B_w=1.179B_s\\\\B=\sqrt{(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{3}A)+1.179(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{-3}A)}\\\\B=2.958\times10^{-5}T$

Hence, the magnetic field is $B=2.958\times10^{-5}T$

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3 years ago