Answer:
680 Kg.m/s
Explanation:
Mass of player; m_p = 105 kg.
Speed of player before Collision; v_pi = 8.5 m/s
Mass of referee; m_r = 85 kg
Speed of referee before collision; v_ri = 3.5 m/s
Speed of referee after collision; v_rf = 6 m/s
From conservation of momentum,
Initial momentum = final momentum
Thus;
(m_p × v_pi) + (m_r × v_ri) = (m_p × v_pf) + (m_r × v_rf)
Where (m_p × v_pf) is the momentum of the player after collision.
Thus, Plugging in the relevant values, we have;
(105 × 8.5) + (85 × 3.5) = (m_p × v_pf) + (85 × 6)
(m_p × v_pf) = (105 × 8.5) + (85 × 3.5) - (85 × 6)
(m_p × v_pf) = 680 Kg.m/s
