A person who has a job that requires working all night and sleeping during the day will end up fighting hos or her natural
2 answers:
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Answer:
Now when it will reach at point B then its normal force is just equal to ZERO
Explanation:
Since we need to cross both the loops so least speed at the bottom must be
also by energy conservation this is gained by initial potential energy
so we will have
now we have
here we have
R = 7.5 m
so we have
Now when it will reach at point B then its normal force is just equal to ZERO
now when it reach point C then the speed will be
now normal force at point C is given as
Refer to the diagrams shown below.
The normal reaction of the road on the automobile is equal to the weight of the automobile (Newtons 3rd Law).
That is,
N = mg (g = 9.8 m/s²)
When the road surface is dry, the resisting frictional force at the wheel is
F₁ = μ₁N
where
μ₁ = the kinetic coefficient of friction.
The value of μ₁ is about 0.7 - 0.9 on a dry road.
When the road is wet, the resisting frictional force is
F = μ₂N
where
μ₂ = the kinetic coefficient of friction on a wet road.
The value of μ₂ is about 0.1 - 0.4 on a wet road.
Because μ₂ < μ₁, the automobile tends to slip on a wet road, especially if the tires are worn.
The normal reaction of the road on the automobile is equal to the weight of the automobile (Newtons 3rd Law).
That is,
N = mg (g = 9.8 m/s²)
When the road surface is dry, the resisting frictional force at the wheel is
F₁ = μ₁N
where
μ₁ = the kinetic coefficient of friction.
The value of μ₁ is about 0.7 - 0.9 on a dry road.
When the road is wet, the resisting frictional force is
F = μ₂N
where
μ₂ = the kinetic coefficient of friction on a wet road.
The value of μ₂ is about 0.1 - 0.4 on a wet road.
Because μ₂ < μ₁, the automobile tends to slip on a wet road, especially if the tires are worn.