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Akimi4 [234]
4 years ago
6

3. Which relation is a function?

Mathematics
1 answer:
Pani-rosa [81]4 years ago
6 0

Answer:

B

Step-by-step explanation:

Recall that functions are defined only if for each value in the domain produces one and only one value in the range.

If we view the relations in the questions as x-y coordinates, this means that for every x-value, you can only have one y-value

Lets evaluate the options:

A) we can see that for x = -3, this gives 2 possible values for y i.e (-3,4) and (-3,8) (hence this is not a function)

C) we can see that for x = 3, this gives 2 possible values for y i.e (3,-8) and (3,8) (hence this is not a function)

D) we can see that for x = -3, this gives 2 possible values for y i.e (-3,4) and (-3,8) (hence this is not a function)

the only choice where this doesn't occur is choice B

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By the third day of a particular week, 2 accidents have already occurred in the intersection. What is the probability that there
Leona [35]

Answer:

The right answer is "0.70".

Step-by-step explanation:

The given query seems to be incomplete. Please find below the attachment of the full query.

By using the Bayes' theorem, we get

⇒  P[(X

By putting the values, we get

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                                     =\frac{0.35}{0.5}

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3 years ago
12) 36 gallons is equal to how many quarts? 4 qt=1 gallon*
guapka [62]

Answer:

144

Step-by-step explanation:

36 x 4

5 0
3 years ago
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What is the equation of a circle with its center at (10,−4) and a radius of 2?
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7 0
3 years ago
2sec^2x - secx - 1 = 0
Ivenika [448]
What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0


Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1


I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
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This is how i worked it out.
Good Luck

4 0
4 years ago
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