A wheel turn 90 revolution per minute How many degrees dose it turn through in 1 second?

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

5 0

Answer:

Step-by-step explanation:

trust me

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A contador is buidling the base of a circular fountain. On the blueprint the base of a circular fountain. The blueprint has scal

max2010maxim [7]

You would need to know how many centimeters the base of the fountain on the blueprint is first. It seems like you are missing some information on this problem.

I'll give you an example anyways.
Let's say the base on the blueprint is 36 centimeters.
1 cm= approximately 0.03 feet
0.03* 36= about 1.08 feet.

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3 years ago

3x-x-5=2(x+2) -9<br> please help

irga5000 [103]

Answer:

infinite solutions

Step-by-step explanation:

Simplify 3x-x-53x−x−5 to 2x-52x−5.

2x-5=2(x+2)-92x−5=2(x+2)−9

2 Expand.

2x-5=2x+4-92x−5=2x+4−9

3 Simplify 2x+4-92x+4−9 to 2x-52x−5.

2x-5=2x-52x−5=2x−5

4 Since both sides equal, there are infinitely many solutions.

Infinitely Many Solutions

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4 years ago

Read 2 more answers

Lines & and m are intersected by transversalt and 2 im.

adelina 88 [10]

I’m not sure on how
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3 years ago

Using Pythagorean inequalities, determine which of the following sets of values can represent the lengths of the sides of an acu

seropon [69]

Answer:

Step-by-step explanation:

$a,\ b,\ c-\text{sides of a triangle}\\\\\text{If}\ a\leq b< c\ \text{and}\ a^2+b^2=c^2,\ \text{then it's the lengths of the sides of a right triangle}\\\\\text{If}\ a\leq b\leq c\ \text{and}\ a^2+b^2>c^2,\ \text{then it's the lengths of the sides of a acute triangle}\\\\\text{If}\ a\leq b< c\ \text{and}\ a^2+b^2$

$\text{Triangle condition:}\\\text{That each side has to be shorter than the sum of the other two sides}\\\text{and longer than their difference.}\\\\\text{If}\ a\leq b\leq c,\ \text{then}\ a+b>c.$

$--------------------------\\a.\\a=1,\ b=2,\ c=3\\\\a+b=1+2=3=c\\\\\text{These are not the lengths of the sides of the triangle.}\\----------------------------\\b.\\a=6,\ b=8,\ c=10\\\\a+b=6+8=14>10=c\qquad OK\\\\a^2+b^2=6^2+8^2=36+64=100\\\\c^2=10^2=100\\\\a^2+b^2=c^2\\\\\text{It's the right triangle.}\\----------------------------$

$c.\\a=6,\ b=7,\ c=8\\\\a+b=6+7=13>8\qquad OK\\\\a^2+b^2=6^2+7^2=36+49=85\\\\c^2=8^2=64\\\\a^2+b^2>c^2\\\\\text{It's the acute triangle.}\\----------------------------\\d.\\a=4,\ b=6,\ c=10\\\\a+b=4+6=10=c\\\\\text{These are not the lengths of the sides of the triangle.}$