Question

Find the kissing lengths of the sides of the triangle.

Answer 1

Answer: The last option.

Step-by-step explanation:

The triangle shown in the figure attached is a right triangle.

1. You can calculate the lenght a as following:

$sin\alpha=\frac{opposite}{hypotenuse}$

$opposite=a\\hypotenuse=6in\\\alpha=30\°$

Substitute values and solve for a. Then, you obtain:

$sin(30\°)=\frac{a}{6in}\\a=6in*sin(30\°)\\a=3in$

2.  You can calculate the lenght b as following:

$cos\alpha=\frac{adjacent}{hypotenuse}$

$adjacent=b\\hypotenuse=6in\\\alpha=30\°$

Substitute values and solve for b. Then, you obtain:

$cos(30\°)=\frac{b}{6in}\\b=6in*cos(30\°)$

$b=3\sqrt{3}in$