How many solutions would there be for the following systems of equations y=3x-56x-2y=10
1 answer:
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Answer: x ≤ -14
Step-by-step explanation:
3 - x ≥ 10
1) You want to subtract 3 from both sides of the equation: 3 - x ≥ 10
-3 -3
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2) Once you subtract 3 from both sides of the equation you'll be able to cancel out 3-3.
3) After, you'll be left with; -x ≥ 7
4) You'll then want to divide both sides by - to isolate x.
5) Divide 7 by -
6) X ≥ -14, but then you'll want to flip the inequality since you divided by a negative.
7) X ≤ -14