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2 years ago

How many solutions would there be for the following systems of equations y=3x-56x-2y=10

Mathematics

1 answer:

Ann [662]2 years ago

6 0

Answer:

So the solution would be (1,-2). Remember you can always validate that the solution is correct by plugging it into both equations. But this is the same as the first equation, y=3x-5. Since they are the SAME line they will have infinite solutions.

Step-by-step explanation:

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20 POINTS !! IF YOU ANSWER THE QUESTIONS !

tatuchka [14]

12 the answer is 12 I know it

6 0

2 years ago

Please Help!!! DUE NOW!

Alexxandr [17]

Answer: 37

Step by step explanation:

y+29+40+2y=180°( sum of angle in straight line)

or, y+2y+29+40=180°

or,3y+69=180

or,3y=180-69

or,3y=111

or,y=111/3

y=37

hope it helps

Good luck on your assignment

5 0

3 years ago

What numbers does the square root of 125 fall between

attashe74 [19]

9 and 10

11 and 12

13 and 14

15 and 16

the square root of 125 is 11.18 so therefore it falls between 11 and 12

3 0

2 years ago

Read 2 more answers

The centers for disease control and prevention reported that 25% of baby boys 6-8 months old in the united states weigh more tha

melisa1 [442]

Answer:

0.1971 ( approx )

Step-by-step explanation:

Let X represents the event of weighing more than 20 pounds,

Since, the binomial distribution formula is,

$P(x)=^nC_r p^r q^{n-r}$

Where, $^nC_r=\frac{n!}{r!(n-r)!}$

Given,

The probability of weighing more than 20 pounds, p = 25% = 0.25,

⇒ The probability of not weighing more than 20 pounds, q = 1-p = 0.75

Total number of samples, n = 16,

Hence, the probability that fewer than 3 weigh more than 20 pounds,

$P(X$

$=^{16}C_0 (0.25)^0 (0.75)^{16-0}+^{16}C_1 (0.25)^1 (0.75)^{16-1}+^{16}C_2 (0.25)^2 (0.75)^{16-2}$

$=(0.75)^{16}+16(0.25)(0.75)^{15}+120(0.25)^2(0.75)^{14}$

$=0.1971110499$

$\approx 0.1971$

3 0

3 years ago

In the first week of July, a record 1100 people went to the local swimming pool. In the second week, 125 fewer people went to

Vladimir [108]

In July:
First week:
Number of people went to the local swimming pool =1040
Second week:
110 fewer people went to the pool than in the first week
so,
Number of people went to the local swimming pool =1040-110
=930
Third week:
130 more people went to the pool than in the second week
so,
Number of people went to the local swimming pool =930+130
=1060
Fourth week:
228 fewer people went to the pool than in the third week
so,
Number of people went to the local swimming pool =1060-228
=832
Decrease in number of people over four week= number of people in first week - number of people in fourth week
Decrease in number of people over four week=1040-832
=208
now, we can find percentage
Percentage is

=20%.........Answer

6 0

3 years ago

How many solutions would there be for the following systems of equations y=3x-56x-2y=10​

How many solutions would there be for the following systems of equations y=3x-56x-2y=10