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3 years ago

How many solutions would there be for the following systems of equations y=3x-56x-2y=10

Mathematics

1 answer:

Ann [662]3 years ago

6 0

Answer:

So the solution would be (1,-2). Remember you can always validate that the solution is correct by plugging it into both equations. But this is the same as the first equation, y=3x-5. Since they are the SAME line they will have infinite solutions.

Step-by-step explanation:

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Step-by-step explanation:

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4 years ago

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vladimir2022 [97]

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Step-by-step explanation:

Order of Operations: BPEMDAS

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4 years ago

The marketing director of a large department store wants to estimate the average number of customers who enter the store every f

Dahasolnce [82]

Answer:

$36.5674\leq x'\leq61.4326$

Step-by-step explanation:

If we assume that the number of arrivals is normally distributed and we don't know the population standard deviation, we can calculated a 95% confidence interval to estimate the mean value as:

$x-t_{\alpha /2}\frac{s}{\sqrt{n} } \leq x'\leq x-t_{\alpha /2}\frac{s}{\sqrt{n} }$

where x' is the population mean value, x is the sample mean value, s is the sample standard deviation, n is the size of the sample, $\alpha$ is equal to 0.05 (it is calculated as: 1 - 0.95) and $t_{\alpha /2}$ is the t value with n-1 degrees of freedom that let a probability of $\alpha/2$ on the right tail.

So, replacing the mean of the sample by 49, the standard deviation of the sample by 17.38, n by 10 and $t_{\alpha /2}$ by 2.2621 we get:

$49-2.2621\frac{17.38}{\sqrt{10} } \leq x'\leq 49+2.2621\frac{17.38}{\sqrt{10} }\\49-12.4326\leq x'\leq 49+12.4326\\36.5674\leq x'\leq61.4326$

Finally, the interval values that she get is:

$36.5674\leq x'\leq61.4326$

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3 years ago

How many solutions would there be for the following systems of equations y=3x-56x-2y=10​

How many solutions would there be for the following systems of equations y=3x-56x-2y=10