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shusha [124]
3 years ago
13

What is the simplest form of the expression 6x(x − 4) − 16x2 − (9x − 1)

Mathematics
1 answer:
BigorU [14]3 years ago
5 0
If the term in the middle is 16x^2

6x^2-24x-16x^2-9x+1 =

-10x^2-33x+1

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(x-2)e2/3=49<br><img src="https://tex.z-dn.net/?f=%28x%20-%202%29%20%5E%7B2%20%5Cdiv%203%7D%20%20%3D%2049%20" id="TexFormula1" t
fredd [130]

\bf (x-2)^{2\div 3}=49\implies (x-2)^{\frac{2}{3}}=7^2\implies \stackrel{\textit{raising both sides by }\frac{3}{2}}{\left( (x-2)^{\frac{2}{3}} \right)^{\frac{3}{2}}=(7^2)^{\frac{3}{2}}} \\\\\\ (x-2)^{\frac{2}{3}\cdot \frac{3}{2}}=7^3\implies (x-2)^1=7^3\implies x=7^3+2\implies x=345

4 0
3 years ago
Ples help smart redstoners
morpeh [17]
44because when you do the math it came out to that
8 0
3 years ago
Read 2 more answers
Kendra has $ 7.75 $7.75 in nickels and quarters. if she has 13 13 more quarters than nickels, how many of each coin does she hav
Ludmilka [50]
Total of $7.75
13 more quarters than nickels

15 nickels = $0.75
28 quarters = $7.00

28 - 15 = 13 coins
$7.00 + $0.75 = $7.75


She has 15 nickels and 28 quarters.
7 0
3 years ago
Which of the following points is a solution of y &gt; Ixl + 5?
Step2247 [10]

Answer:

B. (1,7)

Step-by-step explanation:

We can substitute the x and y values of each coordinate into the inequality and test if they work.

Let's start with A, 5 being y and 0 being x .

5 > |0|+5\\5> 0+5\\5 > 5

5 IS NOT greater than 5, they are the exact same, so A is out.

Let's try B, 1 being x and 7 being y.

7 > |1| + 5\\7 > 1 + 5\\7 > 6

7 IS greater than 6, so B. (1,7) does work for this inequality!

Let's do C for fun, when 7 is x and 1 is y.

1 > |7| + 5\\1>7+5\\1>12

1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.

Therefore B. (1,7) works for the inequality of y > |x|+5.

Hope this helped!

7 0
3 years ago
Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees a
Aliun [14]

Answer:

70 groups

Step-by-step explanation:

5c_{3}*7c_{1}

=\frac{5*4*3}{3*2*1} *\frac{7}{1} \\=70

3 0
3 years ago
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