Answer:
11g + 19
Hope this helps
Step-by-step explanation:
For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.
Feel free to ask further questions!
Answer:
Step-by-step explanation:
6*( 5 + X) = 36
30 + 6X = 36
6X = 6
X = 1
Scale factor is a ratio, you have to remember that. divide the lengths and you will see a constant cratio
Step-by-step explanation:
Given the height of the rocket y in feet related to time after launch x related by the equation:
Y=-16x^2+189x+79
The rocket will hit the ground when y = 0
The equation will become:
0=-16x^2+189x+79
Rearrange
-16x^2+189x+79 = 0
multiply though by minus
16x^2-189x-79 = 0
Factorize and solve for x:
x = 189±√189²-4(16)(-79)/2(16)
x = 189±√35721+5056/32
x = 189±√40777/32
x = 189±201.93/32
x = 189+201.93/32
x = 390.93/32
x = 12.22secs
hence the rocket will hit the ground after 12.22seconds (to the nearest hundredth of a sec)
