Algebraic expression is the expression which consist the variables, coefficients and the constants. The expression for the condition given in the problem is
.
Given information
A cab driver is paid $6 plus $0.45 per mile driven.
Total number of total miles is <em>m.</em>
<h3>
Algebraic expression</h3>
Algebraic expression is the expression which consist the variables, coefficients and the constants. The algebraic expression are used to solve the condition based problems by expressing them into the algebraic form.
As the cab driver is paid $6 as the fixed amount of the taxi irrespective to the mile driven. Thus this is independent to the other variables and written as the constant in the expression.
As the total miles driven by the cab driver is<em> m</em>. The cost of the per mile driven the car is $0.45. Thus the expression for this condition can be given as,

Hence, the expression for the condition given in the problem is
.
Learn more about the algebraic expression here;
brainly.com/question/953809
<u>Question 1</u>
If we let
, then
.
Also, as
bisects
, this means
.
Thus, by the intersecting chords theorem,

However, as distance must be positive, we only consider the positive case, meaning FE=9
<u>Question 2</u>
If we let CE=x, then because AB bisects CD, CE=ED=x.
We also know that since FB=17, the radius of the circle is 17. So, this means that the diameter is 34, and as AE=2, thus means EB=32.
By the intersecting chords theorem,

However, as distance must be positive, we only consider the positive case, meaning CE=8
You could first solve for y, assuming x is 0, and y = 6. Then solve for x, and that means y = 4.
(by far the most painful question all day) 226 mins = 3.77 hours 4 3/5 hours = 4.6 hours 4.6- 3.77 = 0.83 hours 0.83 hours = 49.8 mins = 2988 seconds.
a vertical axis, I assume it means a vertical axis of symmetry, thus it'd be a vertical parabola, like the one in the picture below.
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \qquad \leftarrow vertical\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=0\\ k=0 \end{cases}\implies y=a(x-0)^2+0 \\\\\\ \textit{we also know that } \begin{cases} x=-2\\ y=3 \end{cases}\implies 3=a(-2-0)^2+0\implies 3=4a \\\\\\ \cfrac{3}{4}=a~\hspace{10em}y=\cfrac{3}{4}(x-0)^2+0\implies \boxed{y=\cfrac{3}{4}x^2}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cqquad%20%5Cleftarrow%20vertical%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20h%3D0%5C%5C%20k%3D0%20%5Cend%7Bcases%7D%5Cimplies%20y%3Da%28x-0%29%5E2%2B0%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bwe%20also%20know%20that%20%7D%20%5Cbegin%7Bcases%7D%20x%3D-2%5C%5C%20y%3D3%20%5Cend%7Bcases%7D%5Cimplies%203%3Da%28-2-0%29%5E2%2B0%5Cimplies%203%3D4a%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B3%7D%7B4%7D%3Da~%5Chspace%7B10em%7Dy%3D%5Ccfrac%7B3%7D%7B4%7D%28x-0%29%5E2%2B0%5Cimplies%20%5Cboxed%7By%3D%5Ccfrac%7B3%7D%7B4%7Dx%5E2%7D)