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Anit [1.1K]
3 years ago
9

I don't really know how to graph translations can anyone help me?

Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0
A' will be the new value of A

ok, so the original points are
A=(-4,4)
B=(0,4)
C=(1,2)
D=(-3,2)

(x,y)
x is how far to right and y is how far up
movement left is minus x
movement down is minus y

so 4 right and 1 down
add 4 to every x and minus 1 from every y

A=(-4,4) becomes (0,3)
B=(0,4) becomes (4,3)
C=(1,2) becomes (5,1)
D=(-3,2) becomes (1,1)

A'=(0,3)
B'=(4,3)
C'=(5,1)
D'=(1,1)
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Find the GCF of the terms of the polynomial. 30x3 + 16x5<br> a. x3<br> b. 2x3<br> c. 2x5<br> d. 16x
Vladimir79 [104]
You can take out 2x^3 from both terms making it
2x^3 (15+8x^2)
Answer is B
3 0
3 years ago
Please help me on this
laiz [17]

Answer:

34

Step-by-step explanation:

Angles 3 and 7 are corresponding angles. When the lines defining the base of the corresponding angles are parallel (as in this case where a is parallel to b), then the angles are equal.

That's the heavy duty definition. It just means that corresponding angles in parallel lines are equal.

So if <3 = 34 degrees, then <7 = 34 degrees.

7 0
3 years ago
Shawn earned $2.77 per day for three days as interest on his $1,000.00 investment. What percent interest did he earn in total? G
Nady [450]

Answer: He earned 0.831% interest in total.

Step-by-step explanation:

Given: Shawn earned $2.77 per day for three days as interest on his $1,000.00 investment.

Interest per day = $2.77

Interest in 3 days = 3 x ($2.77)

= $8.31

Invested amount= $1000

Required percentage of earnings = \dfrac{\text{Interest earned in 3 days}}{\text{Initial investment}}\times100

=\dfrac{8.31}{1000}\times100=0.831\%

Hence, he earned 0.831% interest in total.

7 0
3 years ago
What is the value of Y
Keith_Richards [23]
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4 0
3 years ago
Jim went to the playground. He played on the swings for 45 minutes and went on the slide for 55 minutes. It was 4:35 P.M. when J
aleksklad [387]

Answer:

2:55 P.M.

Step-by-step explanation:

First, add the amount of time Jim played outside; 45+55=100

100 minutes is equal to 1 hour 40 minutes.

If he left the playground at 4:35 P.M., then you have to subtract in order to find out when he arrived there.

Subtract 1 hour 40 minutes from 4:35 P.M. to then get 2:55 P.M.

To confirm your answer, you can add back the 1 hour and 40 minutes to 2:55 P.M. and you'll get 4:35 P.M.; back with what you started with.

Hope this helped !!!

4 0
3 years ago
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