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3 years ago

What is the decimal expansion of the following fraction 1/5 A.0.2 B.1.5 C.0.2 D.0.15

Mathematics

1 answer:

hoa [83]3 years ago

3 0

The answer is A) 0.2

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Can someone help me. I need to show the box method also can someone show me.

sveta [45]

there's a 3 on the left of the box it got cut out. you jus multiply 3 by 6000, 200, 50, nd 3,, n then add the numbers tht you get in the boxes and if you see my bad handwriting, no you didnt

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3 years ago

3n - 5 = -8(6 + 5n) <br><br> what does n equal?

Mariana [72]

3n - 5 = -8(6 + 5n)

3n - 5 = -48 - 40n

3n + 40n = -48 + 5

43n = -43

n = -1

8 0

3 years ago

Read 2 more answers

Write the partial fraction decomposition fro the ration expression below

zlopas [31]

$\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}$
$5x-2=a(x-1)+b$

Since $5x-2=5x-5+3=5(x-1)+3$ , it follows that $a=5$ and $b=3$ , so

$\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}$

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}$
$x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2$
$x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b$

When $x=0$ , you find that $b=2$ . It's also clear that $a=1$ . So the remaining constants must be $1+c=1\implies c=0$ and $2+d=1\implies d=-1$ , and so you get

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}$

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3 years ago

Evaluate each absolute value expression below. | 2 | + | 4 | | − 3 | + | 5 | | − 7 | + | − 1 | − | 6 |

soldier1979 [14.2K]

Answer:

| 2 | + | 4 | = 6

| − 3 | + | 5 | = 8

| − 7 | + | − 1 | − | 6 | = 2

Anything that is an absolute value is positive so you just add the numbers normally... even if the numbers are negative..

( if you have any questions please comment on this question so I can help you)

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3 years ago

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Which two students wrote equations to have no solution

Vesna [10]

Answer:

I believe its D

Step-by-step explanation:

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3 years ago