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3 years ago

3. What is the scale factor of Figure B to Figure A?

Mathematics

1 answer:

xxMikexx [17]3 years ago

4 0

Answer:

2.5

Step-by-step explanation:

From the diagram, figure B was enlarged to obtain figure A.

The two figures are therefore similar.

The corresponding sides are in the same proportion. That constant value of the proportion is called scale factor.

It is given by:

$k = \frac{image \: length}{corresponding\:object \: length}$

Figure B is the image of A

$k = \frac{10}{4} = \frac{25}{10} = \frac{21.5}{8.6} = 2.5$

Therefore the scale factor is 2.5

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Shtirlitz [24]

Answer:

perimeter of figure A is 40 cm

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3 years ago

What is the slope of the line that goes through (2, 5) and (-6, -2) ?

alexira [117]

Answer:
slope = 7/8

Explanation:
Slope of the line can be calculated using the following equation:
slope = $\frac{y2 - y1}{x2 - x1}$

The two points given are:
(2,5) representing (x1 , y1)
(-6,-2) representing (x2 , y2)

Substitute with the points in the above equation to get the slope as follows:
slope = $\frac{-2 - 5}{-6 - 2}$ = 7/8

Hope this helps :)

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3 years ago

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mestny [16]

Hey there :)

( 5y + 9 )( 6y - 1 )

We need to use FOIL to expand, that is
First Terms
Outer Terms
Inner Terms
Last Terms

First Outer Inner Last
( 5y )( 6y ) + ( 5y )( - 1 ) + 9 ( 6y ) + 9 ( - 1 )
30y² - 5y + 54y - 9

Combine, if any, the like-terms
30y² + 49y - 9

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3 years ago

Read 2 more answers

What is the volume of the rectangular prims ?

tangare [24]

They are all different sizes.

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3 years ago

Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3

polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

$(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0$

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

#learnwithBrainly

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3 years ago