Question

Glucose is present in blood plasma at a concentration of approximately 80 mg/dL. A typical 70 kg human has approximately 5 L blood, which is 55% plasma. Using the glucose concentration of Sprite that you calculated in the previous question, how many mL of Sprite does a human need to drink to reach a plasma glucose concentration of 80 mg/dL, assuming none is mobilized?

Answer 1

Answer: 48.93 mL of sprite

Volume of blood in 7 Kg human = 5 L

Percentage of plasma in blood = 55%

Volume of plasma in 5 L blood =  (1 L = 10 dL)

Concentration of glucose in plasma = 80 mg/dL

Amount of glucose present in 27.5 dL : 80 mg /dL × 27.5 dL= 2200 mg

Let the volume of sprite with 2200 mg glucose be x

Concentration of glucose in sprite = 44.96 mg/mL

Explanation: