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4 years ago

What is the solution to the equation below? PLEASE PLEASE HELP PLEASE PLEASE PLEASE PROBLEM DOWN BELOW IN THE PHOTO HELP

Mathematics

2 answers:

Strike441 [17]4 years ago

6 0

I think the answer is C
Hope you get it right

anygoal [31]4 years ago

4 0

Answer:

The answer is B, 26/3

I hope this helps!

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What is th resulting true inequality

lorasvet [3.4K]

Answer:

10>-15

Step-by-step explanation:

The given inequality is:

-2<3

The inequality has to be multiplied by -5.

The multiplication is same as multiplying a normal equation with a number. The only difference is that the sign of inequality is changed when it is multiplied with a negative number.

So,

-2(-5) < 3(-5)

10>-15

So the correct answer is the last option ..

8 0

3 years ago

The students in Mr. Nolan's class are writing expressions for the perimeter of a rectangle of side length ? and width w.

uranmaximum [27]

You wanna know witch student is correct?

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3 years ago

What's the prime factorization of 78

Masja [62]

Answer:

2,3 &13

Step-by-step explanation:

78=2times39=3times13

therefore the prime factors of 78=2,3,13

4 0

3 years ago

POSSIBLE PC

bixtya [17]

I think it will be The seconds one so B

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3 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

3 years ago