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3 years ago

What is the solution to the equation below? PLEASE PLEASE HELP PLEASE PLEASE PLEASE PROBLEM DOWN BELOW IN THE PHOTO HELP

Mathematics

2 answers:

Strike441 [17]3 years ago

6 0

I think the answer is C
Hope you get it right

anygoal [31]3 years ago

4 0

Answer:

The answer is B, 26/3

I hope this helps!

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Which expression is equivalent to (3/4)^-2<br> A: -9/16<br> B: 16/9<br> C: -6/8<br> D: 9/16

UkoKoshka [18]

B is the answer B is the answer B is the answer B is the answer

7 0

3 years ago

An equation to find the length in centimeters if the width is 10 cm

Setler79 [48]

10cm X 100 = 1000 is the answer mate

4 0

2 years ago

The mean per capita income is 15,451 dollars per annum with a variance of 298,116. What is the probability that the sample mean

docker41 [41]

Answer: 0.5467

Step-by-step explanation:

Let X be the random variable that represents the income (in dollars) of a randomly selected person.

Given : $\mu=15451$

$\sigma^2=298116\\\\\Rightarrow\ \sigma=\sqrt{298116}=546$

Sample size : n=350

z-score : $\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

To find the probability that the sample mean would differ from the true mean by less than 22 dollars, the interval will be

$\mu-22,\ \mu+22\\\\=15,451 -22,\ 15,451 +22\\\\=15429,\ 15473$

For x=15429

$z=\dfrac{15429-15451}{\dfrac{546}{\sqrt{350}}}\approx-0.75$

For x=15473

$z=\dfrac{15473-15451}{\dfrac{546}{\sqrt{350}}}\approx0.75$

The required probability :-

$P(15429$

Hence, the required probability is 0.5467.

3 0

3 years ago

Please help me this is my last question!!

grin007 [14]

Answer:

You can solve it by saying half times base times perpendicular high

3 0

2 years ago

Two particles, A and B, are initially 37.5 m apart. A is projected in a straight line directly towards B with initial speed 2 ms

Arisa [49]

Answer: 6.66 metres

Step-by-step explanation:

Given that the two particles, A and B, are initially 37.5 m apart.

Acceleration a = velocity/time

Make time t the subject of the formula.

Time t = velocity/acceleration

Time taken by particle A will be

Time t = 2/0.6 = 3.33 seconds

Let's use 2nd equation of motion

S = Ut + 1/2at^2

Distance covered by particle A will be achieved By substitute the values for speed and acceleration into the formula

S = 2 × 3.33 + 1/2 × 0.6 × 3.33^2

S = 6.66 + 0.3 × 11.1

S = 9.99 m

Time taken by particle B will be

Time t = 3/0.4 = 7.5 seconds

Distance covered by particle B will be by using the same formula

S = 3 × 7.5 + 1/2 × 0.4 × 7.5^2

S = 22.5 + 0.2 × 56.25

S = 33.75 metres

Adding the distance covered by particle A

Distance = speed × time

Distance = 2 × 3.33 = 6.66

the distance from A's starting point to C. Is 6.66 metres

6 0

3 years ago