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3 years ago

Help, it’s quite confusing.

Mathematics

1 answer:

Olegator [25]3 years ago

6 0

Lowkey, I'm not sure what this is.

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Please help scatter plot problem multiple choice .

emmasim [6.3K]

I’m not really sure but I think if u search it up u would get it

8 0

3 years ago

A boy spends 4/15 on cloth, 1/5 on food and 5/12 on drink. what fraction is left for other things

mamaluj [8]

Answer:

4/15+1/5+5/12=53/60 so

7/60

Hope This Helps!!!

5 0

2 years ago

Read 2 more answers

4 times a number is 16

andrey2020 [161]

Answer:

4 times 4 equals 16

Step-by-step explanation:

4 times 1= 4

4 times 2= 8

4 times 3= 12

4 times 4= 16

you add 4 after each result.

4 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

Which inequality has a dashed boundary line when graphed? A y>=3/5x+1 B y>= -1/3x+1 C y>3x+1

Ket [755]

Answer: C y>3x+1

Step-by-step explanation:

When we graph an inequality with strictly greater of less than sign ('<' or '>'), then the graph has a dashed boundary line .
Further it indicates that it does not include the points on the line.

From all the given options , only C contains inequality with '>' sign .

Hence, y>3x+1 is the inequality has a dashed boundary line when graphed.

hence, the correct option is C.

4 0

3 years ago