Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.
The people are chosen from the sample without replacement, which is why the <u>hypergeometric distribution</u> is used to solve this question.
Hypergeometric distribution:
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- 1000 people means that

- 130 can wiggle their ears, thus

- Two are selected, thus
.
The probability that neither can wiggle his or her ears is P(X = 0), thus:


0.7568 = 75.68% probability that neither can wiggle his or her ears.
A similar problem is given at brainly.com/question/24826394
Answer:
0.1
Step-by-step explanation:
chance of pulling out a blue marble can be described as 8 equally probable outcomes (blue marbles) out of 20 equally probable outcomes (all marbles).
Similarly, the chance of pulling out a green marble is 5 out of 20.
In total, we have 8*5 (combinations of blue then green) outcomes out of 20*20 (any two marbles):
8*5 / (20*20) = 40 / 400 = 1/10 = 0.1
Answer:
1. (x + 5)(x +10)
2. (x - 7)( x - 8)
3. (x - 4)( x - 7)
4. 2(7x−1)(x−9)
5. (2x+9)(x+6)
6. (x−1)(x−2)
7. (2x+3)(x+8)
8. (9x−2)(x−7)
9. 6(x−6)(x+7)
10. (9x+10)(x−4)
11. (3x+7)(x+3)
12. (x−9)(x−9)
13. 4(9x−10)(x−8)
14. 3(x+3)(x−9)
15. 2(x−1)(x+3)
16. 2(3x−1)(x+2)
17. 5(x−2)(x−2)
18. 2(x−1)(x−2)
Step-by-step explanation:
I'm so sorry it took this long that made my brain hurt it was worth it
Sorry it took so long..
hope I helped!!
B. Because 20 is greter than 18.
Answer:
EF = HG and EF || HG
Step-by-step explanation:
A quadrilateral is a polygon shape with four sides and four angles.
A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:
- Opposite sides are equal and parallel.
- Opposite angles are equal to each other.
- Consecutive angles are supplementary
- The diagonals of a parallelogram bisect each other.
If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG