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n200080 [17]
3 years ago
7

How many total blocks would be needed to build the model for the given base plan?

Mathematics
1 answer:
grigory [225]3 years ago
5 0

Answer:

Well, If you just counted them all, it would be 11.

I added 2+2+1+1+3+2 = 11

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What is the equation of the line perpendicular to y=2x+3.14 going through the points (2,4)?
inessss [21]

Answer:

x+2y-10=0

Step-by-step explanation:

Consider an equation: y=mx+c

Here, m is the slope of the line and c is the y-intercept.

Given equation is y=2x+3.14

Here, slope is m=2

As product of slopes of two perpendicular lines is equal to -1, slope of the required line is m_1=\frac{-1}{m}=\frac{-1}{2}.

Let (x_1,y_1)=(2,4)

Equation of the required line is y-y_1=m_1(x-x_1)

y-4=\frac{-1}{2}(x-2)\\2(y-4)=-1(x-2)\\2y-8=-x+2\\x+2y-8-2=0\\x+2y-10=0

8 0
3 years ago
Find the number of primes less than 190 using the principle of inclusion-exclusion.
Troyanec [42]

The number of primes less than 190 using the principle of inclusion-exclusion are 42

<h3>Principle of inclusion- exclusion</h3>

The principle of inclusion-exclusion is known as a counting technique that computes the number of elements satisfying at least one of several properties and guaranteeing that the numbers are not counted twice.

Prime numbers are numbers only divisible by 1 and itself.

Prime numbers less than 190 are:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181

They are 42 in number

Therefore, the number of primes less than 190 using the principle of inclusion-exclusion are 42

Learn more about prime numbers here:

brainly.com/question/874965

#SPJ11

8 0
2 years ago
Which of the following represents the zeros of f(x) = x3 − 11x2 + 38x − 40?
Delvig [45]
The answer is <span>5, 4, 2
</span>
Among all choices we have 5, so
x = 5
x - 5 = 0
Let's divide the expression by (x - 5) using the long division:
                          x³ - 11x² + 38x - 40
(x - 5)  * x² =      x³ - 5x²                   Subtract
____________________________
                              -6x² + 38x - 40
   (x - 5) * (-6x) =    -6x² + 30x          Subtract
____________________________
                                           8x - 40
                    (x - 5) * 8 =     8x - 40   Sutract
____________________________
                                              0

Thus: x³ - 11x² + 38x - 40 = (x - 5)(x² - 6x + 8)

Now, let's simplify x² - 6x + 8.

x² - 6x + 8 = x² - 2x - 4x + 8 =
                  = x² - 2*x - (4*x - 4*2) = 
                  = x(x - 2) - 4(x - 2) =
                  = (x - 4)(x - 2)

Hence:
x³ - 11x² + 38x - 40 = (x - 5)(x - 4)(x - 2)
To calculate zero:
x³ - 11x² + 38x - 40 = 0
(x - 5)(x - 4)(x - 2) = 0
x - 5 = 0            or             x - 4 = 0              or      x - 2 = 0
x = 5                 or              x = 4                   or      x = 2
3 0
3 years ago
PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!
Mashutka [201]

Answer:

5b^9/a^3

Step-by-step explanation:

3 0
2 years ago
What is the slope of this? HELP PLS
Levart [38]

Answer:

4/5

Step-by-step explanation:

rise over run boi or gerl

7 0
3 years ago
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