I think B :(
ubujujiimijiui
Answer:
Step-by-step explanation:
Count pairs (a, b) whose sum of squares is N (a^2 + b^2 = N)
Given a number N, the task is to count all ‘a’ and ‘b’ that satisfy the condition a^2 + b^2 = N.
Note:- (a, b) and (b, a) are to be considered as two different pairs and (a, a) is also valid and to be considered only one time.
Examples:
Input: N = 10
Output: 2
1^2 + 3^2 = 9
3^2 + 1^2 = 9
Input: N = 8
Output: 1
2^2 + 2^2 = 8
Answer:
Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms
Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728
Now,

So,

Therefore, number of terms is 6