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4 years ago

Which of the following objects have gravitational potential energy?

Physics

2 answers:

Jlenok [28]4 years ago

6 0

Answer:

an apple on a tree branch 3m above the ground

Explanation:

Brut [27]4 years ago

3 0

Answer:

The apple

Explanation:

The apple has gravitational potential energy because it is just sitting there but nothing is pushing it up, it is not sitting on something. This means that it has a lot of gravitational potential energy as nothing is pushing it up.

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What is the diameter of a 12lb shot if the specific gravity is of the shot iron in the shot is 6.8, the density of fresh water 6

marysya [2.9K]

Answer:

The diameter is 0.378 ft.

Explanation:

Given that,

Mass of shot = 12 lb

Density of fresh water = 62.4 lb/ft

Specific gravity = 6.8

We need to calculate the volume of shot

$V = \dfrac{4}{3}\pi r^3\ ft^3$

The density of shot is

Using formula of density

$\rho = \dfrac{m}{V}$

Put the value into the formula

$\rho =\dfrac{12}{ \dfrac{4}{3}\pi r^3}$

We need to calculate the radius

Using formula of specific gravity

$specific\ gravity =\dfrac{density\ of\ shot}{dnsity\ of\ water}$

Put the value into the formula

$6.8=\dfrac{\dfrac{12}{\dfrac{4}{3}\pi r^3}}{62.4}$

$r^3=\dfrac{12}{\dfrac{4}{3}\pi\times6.8\times62.4}$

$r^3=0.0067514$

$r =(0.0067514)^{\frac{1}{3}}$

$r=0.1890\ ft$

The diameter will be

$d = 2\times r$

$d =2\times0.1890$

$d =0.378\ ft$

Hence, The diameter is 0.378 ft.

7 0

3 years ago

Consider the possibility of using two rotating cylinders to replace the conventional wings on an airplane for lift. Consider an

EleoNora [17]

Answer:

27.35m

Explanation:

For the calculation of the Support Force we rely on the formula for obtaining the force in a cylinder of a certain length l,

$F_y = - \rho Ul\Gamma$

Here each term is,

$F_y$ = Lift force

$\rho$ = density of air

$\Gamma$ = vortex strength

For this last equation, its mathematical representation is given by,

$\Gamma = 2\pi av_{\theta}$

Here each term is,

a= 1m, radios of cylinder

$v_{\theta}= 20 Km/hr=5.5m/s$ , the velocity of cylinder surface.

$\Gamma = 2\pi (1)(5.5) = 34.90m^2/s$

In order to find the density of the area at 2000m we will refer to the table of Standard Atmosphere of the United States, that is $1.007kg/m^3,$

$U= 150Km/hr = 41.6m/s, F_y = 40000N, \Gamma = 34.90m^2/s$

Replacing the values,

$40000 = -(1.007)(41.6)l(34.90)$

Clearing l and solving for it we have,

$l=-27.35m$

<em>In this way we can conclude that the length of the cylinder must be 27.35m</em>

7 0

4 years ago

Which objects can be electrically polarized?

SIZIF [17.4K]

neutral objects is correct

5 0

3 years ago

Read 2 more answers

A submersible pump is put under the water at the bottom of a well and is used to push water up through a pipe. What minimum outp

Fantom [35]

Answer:

The Required pressure for this situation is P= 735000Pa

Explanation:

In Determining the required pressure in this situation we use two equations

First one is

F = mg = (ρhA)g

And Second one is

P = $F/A$ = (ρhAg)/A Where P is pressure

We get

P = ρhg

since g = 9.8 m/s and h is given that is 75m and ρ = $1000 kg/m^3$

P = (9.8 m/s)( $1000 kg/m^3$ )(75) we get

P = 735000 Pa

6 0

4 years ago

How would you describe the pattern shown in graph a?

const2013 [10]

That it is going up and that is typically called positive

8 0

4 years ago

Read 2 more answers