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2 years ago

Describe the work performed by a ski lift in terms of kinetic and gravitational potential energy

2 answers:

7 0

Explanation : When the lift falls, then the gravitational energy changed into the kinetic energy. Gravitational potential is associated with the mass of the lift and its position. When lift starts from rest , the mechanical energy of the lift change in the form of potential energy.

When the lift down than the potential energy lost and kinetic energy is gained. Lift loses height and gains speed.

The work is performed by the lift, when lift covers the distance against the gravitational force.

Whitepunk [10]2 years ago

7 0

In order to understand how kinetic and potential energy works in an ski lift it is necessary to know its terms

Potential energy is the energy that a body located from its height above the ground has

Kinetic energy is the energy of a body that is in motion

for the ski lift:

Kinetic Energy: When the ski lift moves from floor to floor

Potential Energy: When the ski lift is standing on the floor and people enter.

Gravitational energy: the chairlift uses the force of gravity to lower and change from potential energy to kinetic energy, with its own weight

I hope its help you

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PWEESE HELP ME WIT MY QUIZ

kaheart [24]

I believe it is acceleration

7 0

3 years ago

Read 2 more answers

As you take your leisurely tour through the solar system, you come across a 1.45 kg rock that was ejected from a collision of as

nikklg [1K]

Answer:

$1.3310\times 10^8 m/s$ is the rock's speed.

Explanation:

Momentum is defined as motion possessed by the moving body's mass. Mathematically it a product of mas and velocity of the body.

$Momentum(P)=Mass(m)\times velocity(v)$

Given : Mass of rock = m = 1.45 kg

Velocity of the rock = v

Momentum of the rock = P = $1.93\times 10^8 kg m/s$

$1.93\times 10^8 kg m/s=1.45 kg\times v$

$v=\frac{1.93\times 10^8 kg m/s}{1.45 kg}=1.33\times 10^8 m/s$

$1.3310\times 10^8 m/s$ is the rock's speed.

6 0

3 years ago

A uniformly charged, straight filament 7.00m in length has a total positive charge of 2.00μC. An uncharged card-board cylinder 2

TEA [102]

The electric field at the surface of the cylinder is 51428V/m

Given data:

• The length of the charge is l= 7m.

• The charge is q = 2μC..

• The radius the cylinder is r = 10 cm

Since the filament length is so large as compared to the cylinder length that the infinite line of charge can be assumed.

The expression to calculate the electric field is given as,

E=2kλ/r

Here, λ is the linear charge density.

Substitute the values in the above equation,

E = (2×9×109N⋅m^2/C^2×2×10^−6C)/0.1m×7m

E = 51428N/C×(V/m)/(N/C)

=51428V/m

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. Matter is positively charged if it contains more protons than electrons, and negatively charged if it contains more electrons than protons.

Learn more about charge here:

brainly.com/question/19886264

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4 0

1 year ago

A jogger runs 4.0 km [W] in 0.50 h, then turns and runs 1.0 km [E] in 0.20 h, then 1.5 km [N] in 0.25 h, then 3.0 km [E] in 0.75

GrogVix [38]

This is a sneaky trick question, to help you discover whether you know
one of the differences between velocity and speed.
=======================================
If you make a list of the distances and directions, and ignore the times,
you find these:

4 - west, (3 + 1) - east . . . . . zero in the east/west direction

1.5 - north, 1.5 - south . . . . . zero in the north/south direction

This jogger went out, had a nice jog around the neighborhood,and ended up exactly where he started.

Average velocity = (distance between start point and end point) / (time)

IF the question asked for average SPEED, then you would need the total distance, and divide it by the total time. But it asks for VELOCITY, and that only involves the straight distance between the start point and the end point, regardless of the route taken in between.

The jogger ended up exactly where he started. The distance between start and end points was zero. Average velocity is (zero) / (time) . And that fraction is going to be Zero, no matter how long or how short the trip was, and no matter how much time it took.

3 0

3 years ago

Read 2 more answers

Calculate the moment of inertia for each scenario: (a) An 80.0 kg skater is approximated as a cylinder with a 0.140 m radius. (b

Zina [86]

Answer:

a) the moment of inertia is 0.784 Kg*m²

b) the moment of inertia is with arms extended is 1.187 Kg*m²

c) the angular velocity in scenario (b) is 4.45 rad/s

Explanation:

The moment of inertia is calculated as

I = ∫ r² dm

since

I = Ix + Iy

and since the cylinder rotates around the y-axis then Iy=0 and

I = Ix = ∫ x² dm

if we assume the cylinder has constant density then

m = ρ * V = ρ * π R²*L = ρ * π x²*L

therefore

dm = 2ρπL* x dx

and

I = ∫ x² dm = ∫ x² 2ρπL* x dx = 2ρπL∫ x³ dx = 2ρπL (R⁴/4 - 0⁴/4) = ρπL R⁴ /2 = mR² /2

therefore

I skater = mR² /2 = 80 Kg * (0.140m)²/2 = 0.784 Kg*m²

b) since the arms can be seen as a thin rod

m = ρ * V = ρ * π R²*L = ρ * π R²*x

dm =ρ * π R² dx

I1 = ∫ x² dm = ∫ x² * ρ * π R² dx = ρ * π R²*∫ x² dx = ρ * π R²* ((L/2)³/3 - (-L/2)³/3)

= ρ * π R²*2*L³/24 = mL²/12

therefore

I skater 2 = I1 + I skater = mL²/12 + mR² /2= 8 Kg* (0.85m)²/12 +(80-8) Kg * (0.140m)²/2 = 1.187 Kg*m²

c) from angular momentum conservation

I s2 * ω s2 = I s1 * ω s1

thus

ω s2 = (I s1 / I s2 )* ω s1 /= (0.784 Kg*m²/1.187 Kg*m²) * 6.75 rad/s = 4.45 rad/s

4 0

3 years ago