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Fiesta28 [93]
3 years ago
6

The gravitational force of attraction between two students sitting at their desks in physics class is 2.59 × 10−8 N. If one stud

ent has a mass of 31.9 kg and the other has a mass of 30.0kg, how far apart are the students sitting? The universal gravitational constant is 6.673 × 10−11 N · m2/kg^2.
Physics
2 answers:
11Alexandr11 [23.1K]3 years ago
4 0

Answer:1.57x10^(-8)m

Explanation:

Force(f)=2.59 x 10^(-8)N

Mass1(M1)=31.9kg

Mass2(M2)=30kg

Gravitational constant(G)=6.673x10^(-11)

Distance apart(d)=?

F=(GxM1xM2)/d^2

2.59x10^(-8)=(6.673x10^(-11)x31.9x30)/d^2

2.59x10^(-8)=(6.39x10^(-8))/d^2

d^2=(6.39x10^(-8))/(2.59x10^(-8))

d^2=2.47x10^(-16)

d=√(2.47x10^(-16))

d=1.57x10^(-8)m

motikmotik3 years ago
3 0
<h2>The distance between students is 2.46 m</h2>

Explanation:

The force of attraction due to Newton's gravitation law is

F = \frac{Gm_1m_2}{r^2}

Here G is the gravitational constant

m₁ is the mass of one student

m₂ is the mass of second student .

and r is the distance between them

Thus r = \sqrt{\frac{Gm_1m_2}{F} }

If we substitute the values in the above equation

r = \sqrt{\frac{6.673x10^-^1^1x31.9x30.0}{2.59x10^-^8} }

= 2.46 m

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what evidence would you expect to find on the moon if it had been subjected to plate tectonics? (select all that apply.)
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Volcanoes and mountains are the evidences that show plate tectonics.

<h3 /><h3>What evidence would you expect to find on the Moon if the Moon had been subjected to plate tectonics? </h3>

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5 0
1 year ago
Need help today please​
Eddi Din [679]

6) True: the car is exerting an equal and opposite force on the truck

7) True: the astronaut can drift back by throwing the tool forward

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6)

This problem can be solved by applying Newton's third law of motion, which states that:

"When an object A exerts a force (action) on another object B, then object B exerts an equal and opposite force (reaction) on object A"

In this problem, we can identify the car and the truck as object A and object B. Here we are told that the truck is exerting a force on the car: therefore, according to Newton's third law, the car is also exerting an equal and opposite force on the truck.

Therefore, the statement is true.

7)

This problem can be also solved by thinking in terms of the Newton's third law of motion.

In fact, at the beginning the astronaut is drifting away from the space station. When he throws away the tool, in the forward direction (away from the space station), he exerts a force on the tool: we can identify this force as the action force, and its direction is away from the space station.

As a result, according to Newton's third law, the tool will also exert a reaction force (equal and opposite) on the astronaut: therefore, the force exerted by the tool on the astronaut is toward the space station, and therefore the astronaut will be pushed back towards the station.

Therefore, the statement is true.

8)

Again, this problem can also be explained using Newton's third law.

In fact, the moment you step on the bug, your foot exerts a force (the action force) on the bug, pushing downward.

As a result, according to Newton's third law, the bug exerts back on you an equal and opposite force (upward). The reason you don't feel this force at all is that your mass is much larger than that of the bug, therefore your acceleration is negligible.

Therefore, the statement is true.

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This problem can be explained by using Newton's second law, which states that the net force acting on an object is equal to the product between its mass and its acceleration. Mathematically:

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In this problem, the ball slows down as it crosses the field: this means that it has an acceleration (more precisely, a negative acceleration). According to the law, this means also that there is a net, unbalanced force acting on it, in the direction opposite to the motion of the ball. In fact, this force is the force of friction between the ball and the surface.

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